In: Statistics and Probability
Sample size = n =200
Probability of failure = p = 0.05
This can be approximated by normal distribution since n is large and
n*p = 200*0.05 =10 and is greater than 5.
The normal approximation is given by:
Mean
Variance :
= 3.08211
What is the likelihood that 10 vests will experience a failure resulting in a serious injury or death?
The probability that 10 vests fail out of 200 is given by:
Applying continuity correction,
=0.5636 - 0.4364
=0.1272
The likelihood that 10 vests will experience a failure resulting in a serious injury or death is 0.1272.
What is the likelihood that they will all be free from defect?
Probability that all vests are free of defect is given by
=0.0010-0.0003
=0.0007
The likelihood that all vests will be free from defect is 0.0007.
What is the likelihood that they will all experience a failure resulting in serious injury or death?
Probability that all vests experience a failure resulting in serious injury or death is given by:
61.484< Z< 61.8085
0.0000
The likelihood that all vests experience a failure resulting in serious injury or death is is 0.0000.