In: Statistics and Probability
Several years ago, 42% of parents who had children in grades K-12 were satisfied with the quality of education the students receive. A recent poll asked 1 comma 055 parents who have children in grades K-12 if they were satisfied with the quality of education the students receive. Of the 1 comma 055 surveyed, 452 indicated that they were satisfied. Construct a 99% confidence interval to assess whether this represents evidence that parents' attitudes toward the quality of education have changed. What are the null and alternative hypotheses? Upper H 0: p ▼ greater than not equals less than equals nothing versus Upper H 1: p ▼ greater than not equals less than equals nothing (Round to two decimal places as needed.)
Sample proportion = 452 / 1055 = 0.428
99% confidence interval for p is
- Z/2 * sqrt [ ( 1 - ) / n ] < p < + Z/2 * sqrt [ ( 1 - ) / n ]
0.428 - 2.576 * sqrt [ 0.428 * ( 1 - 0.428) / 1055 ] < p < 0.428 + 2.576 * sqrt [ 0.428 * ( 1 - 0.428) / 1055 ]
0.389 < p < 0.467
99% CI is ( 0.389 , 0.467 )
The null and alternative hypothesis are
H0: p = 0.42
Ha: p 0.42