The excel data are for the mean body and brain temperature of six ostriches was recorded...

The excel data are for the mean body and brain temperature of six ostriches was recorded at typical hot conditions. The results, in degrees Celsius.

Ostriches live in hot environments, and they are normally exposed to the sun for long periods. Mammals in similar environments have special mechanism for reducing the temperature.

Test for a mean difference in temperature between body and brain for these ostriches. Paste the statistics output from excel
Find the test statistic, p-value
Interpret the results to a person who do not know statistics

Data:

Ostrich	Body temperature	Brain temperature
1	38.51	39.32
2	38.45	39.21
3	38.27	39.2
4	38.52	38.68
5	38.62	39.09
6	38.18	38.94

Solutions

Expert Solution

orchestra answered 1 year ago

Next > < Previous

Related Solutions

Data containing n=130 observations of new born body temperatures produced a mean body temperature of 98.249°...

Data containing n=130 observations of new born body temperatures produced a mean body temperature of 98.249° F. If we know that the standard deviation of body temperature varies by .733° determine if there is evidence to suggest that new born babies have a body temperature different then the adult average of 98.6° F. Use an alpha level of .01 1) State the hypothesis: Ho: Ha: (do not put spaces in these, use the symbols above to copy and paste as...

1. Human Body Temperature. A sample of 115 body temperatures with a mean of 98.20℉ and...

1. Human Body Temperature. A sample of 115 body temperatures with a mean of 98.20℉ and a standard deviation of 0.62℉. Use a 0.05 significance level to test the claim that the mean body temperature of the population is equal to 97.6℉, as is commonly believed. Is there sufficient evidence to conclude that the common belief wrong? 2. Smartphone Users. A Ring Central survey of 395 smartphone users showed that 158 of them said that their smartphone is the only...

A statistician measures 101 randomly selected body temperatures and finds the mean body temperature to be...

A statistician measures 101 randomly selected body temperatures and finds the mean body temperature to be 98.3 with a standard deviation of 0.61. Use a 0.01 significance level to test the claim that the mean body temperature is not 98.6 as is commonly believed. claim: H0: H1: draw a picture compute the test statistic: state whether you reject H0 or fail to rehect H0

2) Human Body Temperature. A sample of 112 body temperatures with a mean of 98.20°F and...

2) Human Body Temperature. A sample of 112 body temperatures with a mean of 98.20°F and a standard deviation of 0.62°F. Use a 0.05 significance level to test the claim that the mean body temperature of the population is equal to 99.6°F, as is commonly believed. Is there sufficient evidence to conclude that the common belief wrong?

2.6 Collins temperature data (Data file: ftcollinstemp) The data file gives the mean temperature in the...

2.6 Collins temperature data (Data file: ftcollinstemp) The data file gives the mean temperature in the fall of each year, defined as Sep- tember 1 to November 30, and the mean temperature in the following winter, defined as December 1 to the end of February in the following calendar year, in degrees Fahrenheit, for Ft. Collins, CO (Colorado Climate Center, 2012). These data cover the time period from 1900 to 2010. The question of interest is: Does the average fall...

1. The numbers below represent the body temperature of six subjects taken at 8am and again...

1. The numbers below represent the body temperature of six subjects taken at 8am and again at 3pm. Use significance level of .05 to test the claim that theres a difference in temperatures due to time of day. 8am 97.8, 97, 98.5, 97.4, 97.4, 99 12am 98, 98.6, 99.1, 98.2, 97.8, 98.8 Please provide Ho,Ha,Right and left tail, two tails, critical value, alpha, test-statistic, p-value, decision and conclusion In a study of the accuracy of fast food orders one restaurant...

A recent study of 30 people indicated that the mean body temperature was 98.2 with a...

A recent study of 30 people indicated that the mean body temperature was 98.2 with a calculated standard deviation of .62 . Test the hypothesis at the α = .05 level that the mean body temperature is not equal to 98.6. Since we have a calculated standard deviation, we must use the adjusted normal table (Table-A3). This is an example of a Two Tail Test.

Supposedly the distribution of the human's body temperature in the population has a mean of 37ºC...

Supposedly the distribution of the human's body temperature in the population has a mean of 37ºC and a standard deviation of 0.85ºC. If a sample of 105 people is chosen, calculate the following probabilities: a) that the mean is less or equal to 36.9 ºC b) that the mean is greater than 38.5 ºC c) Find from what temperature the 10% of the hottest bodies are found d) Find from what temperature the 5% of the coldest bodies are found

It is commonly believed that the mean body temperature of a healthy adult is 98.6 F....

It is commonly believed that the mean body temperature of a healthy adult is 98.6 F. You are not entirely convinced. You collected data using 43 healthy people and found that they had a mean body temperature of 98.21 F with a standard deviation of 1.14 F. Use a 0.05 significance level to test the claim that the mean body temperature of a healthy adult is not 98.6 F. Please do not use a table, use calculator.

For a healthy human, a body temperature follows a normal distribution with Mean of 98.2 degrees...

For a healthy human, a body temperature follows a normal distribution with Mean of 98.2 degrees Fahrenheit and Standard Deviation of 0.26 degrees Fahrenheit. For an individual suffering with common cold, the average body temperature is 100.6 degrees Fahrenheit with Standard deviation of 0.54 degrees Fahrenheit. Simulate 10000 healthy and 10000 unhealthy individuals and answer questions 14 to 16. 14. If person A is healthy and person B has a cold, which of the events are the most likely? Pick...

Subjects