In: Statistics and Probability
Find the missing value required to create a probability distribution, then find the standard deviation for the given probability distribution. Round to the nearest hundredth.
x / P(x) //////// 0 / 0.2 1 / 2 / 0.13 3 / 0.03 4 / 0.05
Solution :
P(X)=0.2+0.13+0.03+0.05=0.41
total =0.41
sum of probabilities are equal to 1 than
P(1)=1-0.41=0.59
Mean = = X * P(X)
= 0 *0.2 + 1 * 0.59 + 2 *0.13 + 3 *0.03 + 4 *0.05
= ( 0+ 0.59 +0.26+0.09+0.2 )
Mean = = 1.14
Standard deviation =
=X 2 * P(X) - 2
= [ 02 * 0.2 + 12 * 0.59 + 22 *0.13 + 32 *0.03 + 42 *0.05 ]-1.142
= [(0 + 0.59 + 0.52 + 0.27+0.8) )]-1.2996
=2.18-1.2996
=0.8804
Standard deviation = =0.94