Question

In: Physics

Please draw the solution without solve the IVP y"+y=dirac function (t-pi/2) y(0)=0, y'(0) . (Label y(t)...

Please draw the solution without solve the IVP y"+y=dirac function (t-pi/2) y(0)=0, y'(0) . (Label y(t) and t number as well) I need a professional expert to answer this question. (be able to follow the comment) (Show the step for what you need to get for drawing this solution as well)

Solutions

Expert Solution

this is basically laplace transforms, if u want how these do, quick google about these will definitly help u out

and i assume y'(0) = 0 .   u missed it in th question

plz comment if u have any doubt, thanks


Related Solutions

Solve y"+y=u(t-pi/2)+3 delta(t-3 pi/2)-u(t-2 pi), by laplace transform methods with y(0)=y'(0)=0.
Solve y"+y=u(t-pi/2)+3 delta(t-3 pi/2)-u(t-2 pi), by laplace transform methods with y(0)=y'(0)=0.
Find the general solution and solve the IVP y''+y'-y=0, y(0)=2, y'(0)=0
Find the general solution and solve the IVP y''+y'-y=0, y(0)=2, y'(0)=0
solve by details y"+y=-1 ,y(0)=0,y(Pi/2)=0 by properties of green function
solve by details y"+y=-1 ,y(0)=0,y(Pi/2)=0 by properties of green function
Solve the IVP by applying the Laplace transform:y''+y=sqrt(2)*sin[sqrt(2)t]; y(0)=10, y'(0)=0
Solve the IVP by applying the Laplace transform:y''+y=sqrt(2)*sin[sqrt(2)t]; y(0)=10, y'(0)=0
apply picard iteration to ivp y’=2y^2, y(0)=1 and solve the solution apply picard iteration to ivp...
apply picard iteration to ivp y’=2y^2, y(0)=1 and solve the solution apply picard iteration to ivp y’=2y^1/2, y(1)=0 and solve the solution
SOLVE the IVP: (D^2+1)y = e^t, y(0) = -1 and y'(0) = 1. Thank you.
SOLVE the IVP: (D^2+1)y = e^t, y(0) = -1 and y'(0) = 1. Thank you.
Use the Laplace transform to solve the IVP: y^'''+y^''+3y^'-5y =16e^(-t); y(0)=0; y'(0)=2; y^'' (0)= -4
Use the Laplace transform to solve the IVP: y^'''+y^''+3y^'-5y =16e^(-t); y(0)=0; y'(0)=2; y^'' (0)= -4
1) . Solve the IVP: y^''+6y^'+5y=0, y(0)=1, y^' (0)=3 2. Find the general solution to each...
1) . Solve the IVP: y^''+6y^'+5y=0, y(0)=1, y^' (0)=3 2. Find the general solution to each of the following: a) y^''+2y^'+5y=e^2x b) y^''+2x/(x^2+1) y'=x c) y^''+4y=1/(sin⁡(2x)) (use variation of parameters)
solve this IVP 9y'' +33.33y' +464.21y=8sin(t/4), y(0)=0, y'(0)=.04
solve this IVP 9y'' +33.33y' +464.21y=8sin(t/4), y(0)=0, y'(0)=.04
using the Laplace transform solve the IVP y'' +4y= 3sin(t) y(0) =1 , y'(0) = -...
using the Laplace transform solve the IVP y'' +4y= 3sin(t) y(0) =1 , y'(0) = - 1 , i am stuck on the partial fraction decomposition step. please explain the decomposition clearly.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT