Question

In: Statistics and Probability

An accounting professor is notorious for being stingy in giving out good letter grades. In a...

An accounting professor is notorious for being stingy in giving out good letter grades. In a large section of 170 students in the fall semester, she gave out only 2% A's, 18% B's, 35% C's, and 45% D's and F's. Assuming that this was a representative class, compute the 85% confidence interval of the probability of getting at least a B from this professor. (You may find it useful to reference the z table. Round intermediate calculations to at least 4 decimal places. Round "z" value and final answers to 3 decimal places.)  

Solutions

Expert Solution

Solution :

Given that,

Point estimate = sample proportion = = 0.18

Z/2 = 1.44

Margin of error = E = Z / 2 * (( * (1 - )) / n)

= 1.44 * (((0.18 * 0.82) / 170)

= 0.042

A 85% confidence interval for population proportion p is ,

- E < p < + E

0.18 - 0.042 < p < 0.18 + 0.042

0.138 < p < 0.222

(0.138 , 0.222)


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