In: Statistics and Probability
On Arvala-7, Jawas are notorious for stealing parts from unattended vehicles. The number of part thefts over a one-month period in 40 randomly selected regional zones have a mean of 5.5 thefts and a standard deviation of 5.8 thefts.
1) Find the standard error for the number of parts thefts on Arvala-7.
2) Construct a 95% confidence interval for the true mean number of such thefts.
3) Interpret the confidence interval by stating your answer in a carefully worded sentence.
Solution :
Given that,
Point estimate = sample mean = = 5.5
sample standard deviation = s = 5.8
sample size = n = 40
Degrees of freedom = df = n - 1 = 40 - 1 = 39
1) SE = (s /n) = ( 5.8 / 40) = 0.917
2) At 95% confidence level
= 1 - 95%
=1 - 0.95 =0.05
/2
= 0.025
t/2,df
= t0.025,39 = 2.023
Margin of error = E = t/2,df * SE
= 2.023 * 0.917
Margin of error = E = 1.86
The 95% confidence interval estimate of the population mean is,
± E
= 5.5 ± 1.86
= ( 3.64, 7.36 )
3) We are 95% confident that the true mean of part thefts over a one-month period between 3.64 and 7.36.