In: Statistics and Probability
M&M plain candies come in various colors. According to the M&M/Mars Department of Consumer Affairs, the distribution of colors for plain M&M candies is as follows.
Color: Purple 23%, Yellow 19%, Red 22%, Orange 9%, Green 6%, Blue 6%, Brown 15%
Suppose you have a large bag of plain M&M candies and you choose one candy at random.
(a) Find P(green candy or blue candy).
Are these outcomes mutually exclusive? Why?
A. Yes. Choosing a green and blue M&M is not possible.
B. No. Choosing a green and blue M&M is not possible.
C. Yes. Choosing a green and blue M&M is possible.
D. No. Choosing a green and blue M&M is possible.
(b) Find P(yellow candy or red candy).
Are these outcomes mutually exclusive? Why?
A. Yes. Choosing a yellow and red M&M is possible.
B. Yes. Choosing a yellow and red M&M is not possible.
C. No. Choosing a yellow and red M&M is not possible.
D. No. Choosing a yellow and red M&M is possible.
(c) Find P(not purple candy).
Solution:
Given:
Color | Percentage |
---|---|
Purple | 23% |
Yellow | 19% |
Red | 22% |
Orange | 9% |
Green | 6% |
Blue | 6% |
Brown | 15% |
Part a) Find P(green candy or blue candy).
P(green candy or blue candy) = P(green candy) + P(blue candy)
P(green candy or blue candy) = 6% + 6%
P(green candy or blue candy) = 12%
P(green candy or blue candy) = 0.12
Are these outcomes mutually exclusive? Why?
A. Yes. Choosing a green and blue M&M is not possible.
Part b) Find P(yellow candy or red candy).
P(yellow candy or red candy) = P(yellow candy) + P(red candy)
P(yellow candy or red candy) = 19%+ 22%
P(yellow candy or red candy) = 41%
P(yellow candy or red candy) = 0.41
Are these outcomes mutually exclusive? Why?
B. Yes. Choosing a yellow and red M&M is not possible.
Part c) Find P(not purple candy).
P(not purple candy) =1 - P( purple candy)
P(not purple candy) =1 - 0.23
P(not purple candy) = 0.77