Question

In: Statistics and Probability

An SAT prep course claims to improve the test score of students. The table below shows...

An SAT prep course claims to improve the test score of students. The table below shows the scores for seven students the first two times they took the verbal SAT. Before taking the SAT for the second time, each student took a course to try to improve his or her verbal SAT scores. Do these results support the claim that the SAT prep course improves the students' verbal SAT scores? Let d=(verbal SAT scores prior to taking the prep course)−(verbal SAT scores after taking the prep course). Use a significance level of α=0.05 for the test. Assume that the verbal SAT scores are normally distributed for the population of students both before and after taking the SAT prep course.

Score on first SAT 470 560 430 590 490 410 460

Score on second SAT 520 620 450 610 530 460 500

Step 2 of 5 : Find the value of the standard deviation of the paired differences. Round your answer to one decimal place.

Solutions

Expert Solution

Solution:

Before after Difference
470 520 -50
560 620 -60
430 450 -20
590 610 -20
490 530 -40
410 460 -50
460 500 -40

Data for the paired difference is

-50,-60,-20,-20,-40,-50,-40,

n = 7

Step 2 of 5 : Find the value of the standard deviation of the paired differences.

x x^2
-50 2500
-60 3600
-20 400
-20 400
-40 1600
-50 2500
-40 1600
SUM -280 12600

Sample variance s2 =

= [1/(7- 1)][12600 - (-2802/7) ]

= 233.333333333

Now ,

standard deviation s = variance = 15.3

Answer : 15.3


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