Question

TABLE 11- 4

An agronomist wants to compare the crop yield of 3 varieties of chickpea seeds. She plants 15 fields, 5 with each variety. She then measures the crop yield in bushels per acre. Treating this as a completely randomized design, the results are presented in the table that follows.

Trial	Smith	Walsh	Trevor
1	11.1	19.0	14.6
2	13.5	18.0	15.7
3	15.3	19.8	16.8
4	14.6	19.6	16.7
5	9.8	16.6	15.2

True or False: Referring to Table 11- 4, the decision made at 0.005 level of significance implies that all 3 means are significantly different.

True

False

Answer 1

Claim: All 3 means are significantly different.

The null and alternative hypothesis is:

H1: At least one of the mean is different.

Level of significance = 0.005

By using excel we can solve this question easily.

First, enter all data into excel.

Click on Data -------> Data Analysis--------> Anova: Single-Factor-----> Input Data -------> Select all data -------> Output Range : Select any empty cell --------> ok

We get

We get Test statistic F = 15.24149

P-value = 0.000508

P-value < 0.005 we reject null hypothesis.

Conclusion:

All 3 means are significantly different.

True