In: Statistics and Probability
A variable of a population has a mean and a standard deviation .
a. The sampling distribution of the sample mean for samples of size 49 is approximately normally distributed with mean and standard deviation of
Mean = 100 and standard deviation = 3 |
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Mean = 14.28 and standard deviation = 3 |
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Mean = 14,28 and standard deviation = 0.428 |
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Mean = 99 and standard deviation = 9 |
Solution,
Sample of Size = 49
Mean = 100 and standard deviation = 3
= = 100
= /
= 3/
= 0.4286
Mean = 14.28 and standard deviation = 3
= = 14.28
= /
= 3/
= 0.4286
Mean = 14.28 and standard deviation = 0.428
= = 14.28
= /
= 0.428/
= 0.0611
Mean = 99 and standard deviation = 9
= = 99
= /
= 9/
= 1.2857