In: Statistics and Probability
It is difficult to determine a person’s body fat percentage accurately without immersing him or her in water. Researchers hoping to find ways to make a good estimate immersed 20 male subjects, then measured their waist shown in the table.
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a) Treating waist as the explanatory variable, x, determine the estimates of ?1and ?0.
S.No | X | Y | (x-x̅)2 | (y-y̅)2 | (x-x̅)(y-y̅) |
1 | 32 | 6 | 25.5025 | 189.06 | 69.4375 |
2 | 36 | 21 | 1.1025 | 1.56 | -1.3125 |
3 | 38 | 15 | 0.9025 | 22.56 | -4.5125 |
4 | 33 | 6 | 16.4025 | 189.06 | 55.6875 |
5 | 39 | 22 | 3.8025 | 5.06 | 4.3875 |
6 | 40 | 31 | 8.7025 | 126.56 | 33.1875 |
7 | 41 | 32 | 15.6025 | 150.06 | 48.3875 |
8 | 35 | 21 | 4.2025 | 1.56 | -2.5625 |
9 | 38 | 25 | 0.9025 | 27.56 | 4.9875 |
10 | 38 | 30 | 0.9025 | 105.06 | 9.7375 |
11 | 33 | 10 | 16.4025 | 95.06 | 39.4875 |
12 | 40 | 20 | 8.7025 | 0.06 | 0.7375 |
13 | 36 | 22 | 1.1025 | 5.06 | -2.3625 |
14 | 32 | 9 | 25.5025 | 115.56 | 54.2875 |
15 | 44 | 38 | 48.3025 | 333.06 | 126.8375 |
16 | 33 | 10 | 16.4025 | 95.06 | 39.4875 |
17 | 41 | 27 | 15.6025 | 52.56 | 28.6375 |
18 | 34 | 12 | 9.3025 | 60.06 | 23.6375 |
19 | 34 | 10 | 9.3025 | 95.06 | 29.7375 |
20 | 44 | 28 | 48.3025 | 68.06 | 57.3375 |
Total | 741 | 395 | 276.9500 | 1737.75 | 615.2500 |
Mean | 37.050 | 19.75 | SSX | SSY | SXY |
sample size : n= | 20 | ||||
here y̅ | = | 19.7500 | |||
x̅ | = | 37.0500 | |||
Sxx | = | 'Σ(Xi-X̅)2= | 276.950 | ||
Sxy = | 'Σ(Xi-X̅)(Yi-Y̅)= | 615.250 | |||
slope= β̂1 = | Sxy/Sxx= | 2.2215 | |||
intercept= β̂0 = | y̅-β1x̅= | -62.5573 |