In: Statistics and Probability
Police response time to an emergency call is the difference between the time the call is first received by the dispatcher and the time a patrol car radios that it has arrived at the scene. Over a long period of time, it has been determined that the police response time has a normal distribution with a mean of 11.2 minutes and a standard deviation of 2.1 minutes. For a randomly received emergency call, find the following probabilities. (Round your answers to four decimal places.)
(a) the response time is between 7 and 13 minutes
(b) the response time is less than 7 minutes
(c) the response time is more than 13 minutes
a)
µ = 11.2
σ = 2.100
we need to calculate probability for ,
7 ≤ X ≤ 13
X1 = 7 , X2 =
13
Z1 = (X1 - µ ) / σ = ( 7
- 11.2 ) / 2.1
= -2.0000
Z2 = (X2 - µ ) / σ = ( 13
- 11.2 ) / 2.1
= 0.8571
P ( 7 < X <
13 ) = P ( -2
< Z < 0.857 )
= P ( Z < 0.857 ) - P ( Z
< -2.000 ) =
0.80432 - 0.022750 =
0.7816
b)
µ = 11.2
σ = 2.1
left tailed
P( X ≤ 7 )
Z =(X - µ ) / σ = ( 7 -
11.2 ) / 2.1
Z = -2.000
P(X ≤ 7 ) = P(Z ≤
-2.00 ) =
0.0228(answer)
excel formula for probability from z score is
=NORMSDIST(Z)
c)
µ = 11.2
σ = 2.1
right tailed
P ( X ≥ 13.00 )
Z = (X - µ ) / σ = ( 13.00
- 11.2 ) / 2.1
= 0.857
P(X ≥ 13 ) = P(Z ≥
0.857 ) = P ( Z <
-0.857 ) =
0.1957(answer)
excel formula for probability from z score is
=NORMSDIST(Z)