Question

In: Statistics and Probability

Police response time to an emergency call is the difference between the time the call is...

Police response time to an emergency call is the difference between the time the call is first received by the dispatcher and the time a patrol car radios that it has arrived at the scene. Over a long period of time, it has been determined that the police response time has a normal distribution with a mean of 11.2 minutes and a standard deviation of 2.1 minutes. For a randomly received emergency call, find the following probabilities. (Round your answers to four decimal places.)

(a) the response time is between 7 and 13 minutes

(b) the response time is less than 7 minutes

(c) the response time is more than 13 minutes

Solutions

Expert Solution

a)

µ =    11.2                              
σ =    2.100                              
we need to calculate probability for ,                                  
7   ≤ X ≤    13                          
X1 =    7   ,   X2 =   13                  
                                  
Z1 =   (X1 - µ ) / σ = (   7   -   11.2   ) /    2.1   =   -2.0000  
Z2 =   (X2 - µ ) / σ = (   13   -   11.2   ) /    2.1   =   0.8571  
                                  
P (   7   < X <    13   ) =    P (    -2   < Z <    0.857   )
                                  
= P ( Z <    0.857   ) - P ( Z <   -2.000   ) =    0.80432   -    0.022750   =    0.7816

b)

µ =    11.2              
σ =    2.1              
left tailed                  
P( X ≤    7   )          
                  
Z =(X - µ ) / σ = (   7   -   11.2   ) /    2.1
Z =    -2.000              
P(X ≤   7   ) = P(Z ≤   -2.00   ) =   0.0228(answer)
excel formula for probability from z score is =NORMSDIST(Z)                  

c)

µ =    11.2                          
σ =    2.1                          
right tailed                              
P ( X ≥   13.00   )                      
                              
Z =   (X - µ ) / σ = (   13.00   -   11.2   ) /    2.1   =   0.857
                              
P(X ≥   13   ) = P(Z ≥   0.857   ) =   P ( Z <   -0.857   ) =    0.1957(answer)
excel formula for probability from z score is =NORMSDIST(Z)                              


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