In: Chemistry
50.0mL of .500M NaOH is added to 25.0mL of .500M HCL in a calorimeter BOth are at an initial temperature of 25 C ans final temperature is 27.21 C. Assume the mass of the final solution is 76.0 g and the Cs of the solution is 4.18 J/gC. what is the value of q for water, what is the value of q for the reaction, what is the change of H of the reaction in kj/mol?
q = ms ΔT = = 76 x 4.18 x(27.21-25) = 702.07 joules
NaOH + HCl --------> H2O + NaCl
t=0 25 12.5 millimoles
t=t 12.5 0 12.5 12.5 millimoles
for 12.5 millimoles ---------> energy is 702.07 joules
for 1 millimoles ----------> 702.07/12.5 Joules
for 1 mole= 1000millimoles -------> 1000x (702.07/12.5) =56165.6 joules
ΔH = 56.165.6KJ /moles