Show that the indicial roots of the singularity x=0 differ by an
integer. Use the method...
Show that the indicial roots of the singularity x=0 differ by an
integer. Use the method of Frobenius to obtain the first four terms
of at least one series solutions of the DE:
I am asked to find the square roots using the bisection method
for x * x - a = 0.
I was wondering how the bisection method is performed.
Let's suppose a = 9, so I would need to find the roots of x * x
- 9 = 0.
Also, from the 1st equation, when would the bisection method NOT
output a root?
(a) Let n = 2k be an even integer. Show that x = rk
is an element of order 2 which commutes with every element of
Dn.
(b) Let n = 2k be an even integer. Show that x = rk
is the unique non-identity element which commutes with every
element of Dn.
(c) If n is an odd integer, show that the identity is the only
element of Dn which commutes with every element of
Dn.
1). Consider the quadratic equation
x^2+ 100 x + 1 = 0
(i) Compute approximate roots by solving
x^2 -100 x = 0
(ii) Use the quadratic formula to compute the roots of
equation
(iii) Repeat the computation of the roots but use 3 digit
precision.
(iv) Compute the relative absolute errors in the two 3 digit
precision root approximations in (iii).
(v) With x1 =1/2a (-b + sqrt b^2 - 4ac and x2 = 1/2a (-b + sqrt b^2...
Use the method of Undetermined Coefficients to find a general
solution of this system X=(x,y)^T
Show the details of your work:
x' = 6 y + 9 t
y' = -6 x + 5
Note answer is: x=A cos 4t + B sin 4t +75/36; y=B cos
6t - A sin 6t -15/6 t
Implement in MATLAB the Newton-Raphson method to find the roots
of the following functions.
(a) f(x) = x 3 + 3x 2 – 5x + 2
(b) f(x) = x2 – exp(0.5x)
Define these functions and their derivatives using the @ symbol.
For example, the function of part (a) should be f=@(x)x^3 + 3*x.^2
- 5*x + 2, and its derivative should be f_prime=@(x)3*x.^2 + 6*x -
5.
For each function, use three initial values for x (choose
between -10...
Find y as a function of x:
y'''-12y''+27y'=80e^x
y(0)=29
y'(0)=11
y''(0)=21
I found the roots to be r=0,3,9 and c1=224/9 c2=13/3 c3=-2/9
not sure what is wrong with the answer I'm entering.