In: Statistics and Probability
For a data set obtained from a sample, n = 79 and x = 45.30 . It is known that o = 4.1.
a. What is the point estimate of u?
The point estimate is ????????.
b. Make a 90% confidence interval for u .
Round your answers to two decimal places.
(???????, ??????)
c. What is the margin of error of estimate for part b?
Round your answer to three decimal places.
E =???????
Solution :
Given that,
Point estimate = sample mean =
= 45.30
Population standard deviation =
= 4.1
Sample size = n =79
(a) Point estimate =45.30
At 90% confidence level the z is ,
= 1 - 90% = 1 - 0.90 = 0.1
/ 2 = 0.1 / 2 = 0.05
Z/2 = Z0.05 = 1.645 ( Using z table )
Margin of error = E = Z/2
* (
/n)
= 1.645 * ( 4.1 / 79
)
E= 0.7588
(b)At 90% confidence interval estimate of the population mean
is,
- E <
<
+ E
45.30- 0.7588 <
< 45.30+ 0.7588
44.5412 <
< 46.0588
(44.54 , 46.06 )
(c)Margin of error = E = 0.759