Question

In: Statistics and Probability

Suppose babies born in a large hospital have a mean weight of 4088 grams, and a...

Suppose babies born in a large hospital have a mean weight of 4088 grams, and a variance of 55,696

If 128 babies are sampled at random from the hospital, what is the probability that the mean weight of the sample babies would be greater than 4132 grams? Round your answer to four decimal places.

Solutions

Expert Solution

µ =    4088                                      
σ =    236                                      
n=   128                                      
                                          
X =   4132                                      
                                          
Z =   (X - µ )/(σ/√n) = (   4132   -   4088   ) / (    236   / √   128   ) =   2.109  
                                          
P(X ≥   4132   ) = P(Z ≥   2.11   ) =   P ( Z <   -2.109   ) =    0.0175           (answer)
excel formula for probability from z score is =NORMSDIST(Z)                                          

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