Question

Suppose babies born in a large hospital have a mean weight of 4022 grams, and a standard deviation of 266 grams. If 53 babies are sampled at random from the hospital, what is the probability that the mean weight of the sample babies would differ from the population mean by more than 45 grams? Round your answer to four decimal places.

Answer 1

 

mean = = 4022

standard deviation = = 266

n = 53

= 4022

= / n = 266 / 53

= 1 - P[(-45) / 266 / 53 < ( - ) / < (45) / 266 / 53)]

= 1 - P(-1.23 < Z < 1.23)

= 1 - [P(Z < 1.23) - P(Z < -1.23) ]

= 1 - 0.7813

= 0.2187

Probability = 0.2187