In: Statistics and Probability
The 49 subjects treated with raw garlic had LDL cholesterol measurements with a mean of 151 and a standard deviation of 15, while 48 subjects given placebos had LDL cholesterol measurements with a mean of 149 and a standard deviation of 14.
Use a 0.05 significance level to test the claim that there is no difference between the mean LDL cholesterol levels of subjects treated with raw garlic and subjects given placebos.
ANSWER::
In order to run an independent t-test, we need the following:
The requirements are met.
The hypothesis being tested is:
H0: µ1 = µ2
H1: µ1 ≠ µ2
raw garlic | placebo | |
151 | 149 | mean |
15 | 14 | std. dev. |
49 | 48 | n |
95 | df | |
2.000 | difference (raw garlic - placebo) | |
210.653 | pooled variance | |
14.514 | pooled std. dev. | |
2.947 | standard error of difference | |
0 | hypothesized difference | |
0.679 | t | |
.4991 | p-value (two-tailed) |
The p-value is 0.4991.
Since the p-value (0.4991) is greater than the significance level (0.05), we cannot reject the null hypothesis.
Therefore, we can conclude that there is no difference between the mean LDL cholesterol levels of subjects treated with raw garlic and subjects given placebos.
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