In: Statistics and Probability
Fill amounts of jars of peanuts from a certain factors are known to follow a Normal distribution with mean 454g and standard deviation 15g. Suppose that a random sample of 8 jars is taken. What is the probability that the average weight of this sample is between 451g and 458g?
Solution :
Given that,
mean = = 454
standard deviation = = 15
n = 8
= = 454
= / n = 15/ 8 = 5.30
P(451 < < 458 )
= P[(451- 454) /5.30 < ( - ) / < (458 - 454) /5.30 )]
= P( -0.57< Z < 0.75 )
= P(Z < 0.75) - P(Z < -0.57)
= 0.7734 - 0.2843 = 0.4891
Probability = 0.4891