In: Chemistry
Calculate the theoretical yield of this Williamson Ether Synthesis:
Materials:
25 mL Erlenmeyer flask with stir bar
0.8 mL (0.83g) p-cresol
0.7 mL 1-bromopropane
50 mg (0.05g) t-butyl ammonium bromide
-Add all reagents at room temperature, reflux ~1hr at a 3 setting on a hotplate, cool to room temperature
Workup:
- add 5 mL diethyl ether
-etc.
-etc.
-etc....
Mass of p-cresol = 0.83 g
Molar mass of p-cresol = 108.13 g/mol
Therefore moles of p-cresol = mass of p-cresol/molar mass of p-cresol = 0.83/108.13 = 0.0077 mol
Volume of 1-bromoprpane = 0.7 mL
Density of 1-bromopropane = 1.35 g/mL
Therefore mass of 1-bromopropane = volume of 1-bromopropane x density of 1-bromopropane
= 0.7 x 1.35
= 0.945 g
Molar mass of 1-bromopropane = 123 g/mol
Therefore moles of 1-bromopropane = 0.945/123 = 0.0077 mol
Moles of both of the reactants are same.
From the above equation, it is clear that theoretically 1 mol of each reactant will produce 1 mol of product.
Therefore, 0.0077 mol of each reactant will produce 0.0077 mol of product.
Molar mass of the product = 150.22 g/mol
Therefore, the theoretical yield of the product = 150.22 x 0.0077 = 1.16 g.