In: Statistics and Probability
Suppose you want to test the claim the paired sample data given below come from a population for which the mean difference is ??=0.
x 73 59 88 59 67 86 51
y 67 65 80 55 76 67 57
Use a 0.05 significance level to find the following:
(a) The mean value of the difference ? for
the paired sample data
d¯=
(b) The standard deviation of the
differences ? for the paired sample data
??=
(c) The t-test statistic
?=
(d) The positive critical value
?=
(e) The negative critical value
?=
(f) Does the test statistic fall in the
critical region?
A. No
B. Yes
(g) Construct a 95% confidence interval for
the population mean of all differences x−y.
<??<
a)
dbar = 2.29
b)
sd = 9.9451
c)
Test statistic,
t = (dbar - 0)/(s(d)/sqrt(n))
t = (2.29 - 0)/(9.9451/sqrt(7))
t = 0.609
d)
The positive critical value = 2.447
e)
The negative critical value = -2.447
f)
No
g)
sample mean, xbar = 2.29
sample standard deviation, s = 9.9451
sample size, n = 7
degrees of freedom, df = n - 1 = 6
Given CI level is 95%, hence α = 1 - 0.95 = 0.05
α/2 = 0.05/2 = 0.025, tc = t(α/2, df) = 2.447
ME = tc * s/sqrt(n)
ME = 2.447 * 9.9451/sqrt(7)
ME = 9.198
CI = (xbar - tc * s/sqrt(n) , xbar + tc * s/sqrt(n))
CI = (2.29 - 2.447 * 9.9451/sqrt(7) , 2.29 + 2.447 *
9.9451/sqrt(7))
CI = (-6.91 , 11.49)
-6.91< mud < 11.49