In: Statistics and Probability
Find the variance for the given sample data. Round your answer to one more decimal place than the original data. 3) The weights (in ounces) of 10 cookies are shown. 1.4 0.99 1.37 0.58 0.68 0.57 1.1 0.96 1.2 1.27
Solution:
Given that,
1.4 ,0.99, 1.37 ,0.58, 0.68 ,0.57 ,1.1 ,0.96, 1.2 ,1.27
a) The range =9 -2 = 7
b )The mean of sample is
x/n = (1.4 +0.99+ 1.37 +0.58 +0.68+ 0.57+ 1.1+ 0.96+ 1.2 +1.27 / 10)
= 1.012
The sample mean is 1.012
Sample standard deviation is s
s = 1/(n-1)(x - )2
= 1/4 (1.4 - 1.012 )2+ (0.99- 1.012 )2+ (1.37 - 1.012 )2+ (0.58- 1.012 )2 +( 0.68 - 1.012 )2+(0.57 - 1.012 )2+ (1.1 - 1.012 )2+ (0.96 - 1.012 )2+ (1.2- 1.012 )2 +( 1.27 - 1.012 )2
= 0.098195555555556
=0.31336170084354
The sample standard deviation is 0.3134
variance=( s )2
=( 0.31336170084354 )2
=0.098195555555556
variance=0.10