In: Finance
1. You take out a $20,000, ten-year loan. Equal payments are to be made at the end of each year at an interest rate of 10%. Calculate the appropriate loan table, showing the breakdown in each year between principal and interest.
| Cost | 20,000 | |||
| Payment | $3,254.91 | |||
| Interest | 10% | |||
| Years | 10 | |||
| Division of payment between: | ||||
| Year | 
Principal at beginning of year  | 
Payment at end of year  | 
Interest | Principal | 
| 1 | ||||
| 2 | ||||
| 3 | ||||
| 4 | ||||
| 5 | ||||
| 6 | ||||
| 7 | ||||
| 8 | ||||
| 9 | ||||
| 10 | ||||
| 0.00 | ||||
Annual end-of-year loan payment
Loan Amount (P) = $20,000
Annual Interest Rate (n) = 10% per year
Number of years (n) = 10 Years
Annual Payment = [P x {r (1+r)n} ] / [( 1+r)n – 1]
= [$20,000 x {0.10 x (1 + 0.10)10}] / [(1 + 0.10)10 – 1]
= [$20,000 x {0.10 x 2.59374}] / [2.59374 – 1]
= [$20,000 x 0.25937] / 1.59374
= $5,187.48 / 1.59374
= $3,254.91 per year
“The Annual end-of-year loan payment = $3,254.91 per year”
Loan Amortization Schedule
| 
 Year  | 
 Principal at beginning of year ($)  | 
 Payment at end of year ($)  | 
 Interest Paid at 10% ($)  | 
 Principal ($)  | 
| 
 1  | 
 20,000.00  | 
 3,254.91  | 
 2,000.00  | 
 1,254.91  | 
| 
 2  | 
 18,745.09  | 
 3,254.91  | 
 1,874.51  | 
 1,380.40  | 
| 
 3  | 
 17,364.69  | 
 3,254.91  | 
 1,736.47  | 
 1,518.44  | 
| 
 4  | 
 15,846.25  | 
 3,254.91  | 
 1,584.62  | 
 1,670.29  | 
| 
 5  | 
 14,175.96  | 
 3,254.91  | 
 1,417.60  | 
 1,837.31  | 
| 
 6  | 
 12,338.65  | 
 3,254.91  | 
 1,233.86  | 
 2,021.05  | 
| 
 7  | 
 10,317.60  | 
 3,254.91  | 
 1,031.76  | 
 2,223.15  | 
| 
 8  | 
 8,094.45  | 
 3,254.91  | 
 809.45  | 
 2,445.46  | 
| 
 9  | 
 5,648.99  | 
 3,254.91  | 
 564.90  | 
 2,690.01  | 
| 
 10  | 
 2,958.98  | 
 3,254.91  | 
 295.93  | 
 2,958.98  |