Question

Make 25 mL of a single solution containing 10 mM MOPS [MW=209 g/mole]. How many grams MOPS do you need?

Answer 1

Ans. Given,

            Volume of solution = 25.0 mL = 0.025 L                          ; [1 mL = 0.001 L]

            Molarity of solution = 10.0 mM = 0.010 M                      ; [1 mM = 0.001 M]

Now,

            Required moles of MOPS = Molarity x Volume of solution in liters

                                                = 0.010 M x 0.025 L

                                                = (0.010 mol/ L) x 0.025 L               ; [1 M = 1 mol/ L]

                                                = 0.00025 mol

Required mass of MOPS = Required moles x Molar mass

                                    = 0.00025 mol x (209.0 g/ mol)

                                    = 0.05225 g