Question

In: Statistics and Probability

Based on a survey, workers in Ontario earn an average of $60,000 per year with a...

Based on a survey, workers in Ontario earn an average of $60,000 per year with a known standard deviation of $6000. In an attempt to verify this salary level, a random sample of 36 workers in Ontario was selected. Let X represent the mean salary of these 36 workers.

a) Describe the sampling distribution of X.

b) Calculate the probability that X is between 58,500 and 63,000.

c) What is the 90th percentile for X.

Solutions

Expert Solution

a) The sampling distribution of X is Normally distributed with mean 60000 and standard deviation 1000

b) The probability that X is between 58,500 and 63,000 is 0.9319

c) The 90th percentile for X is 61281.55 61282


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