In: Statistics and Probability
Scores of an IQ test have a bell-shaped distribution with a mean of 100 and a standard deviation of 10. Use the empirical rule to determine the following
a) What percentage of people has an IQ score between 70 and 130?
(b) What percentage of people has an IQ score less than 90 or greater than 110?
(c) What percentage of people has an IQ score greater than 120?
(a)
= 100
= 10
To find P(70 < X < 130):
Case 1: For X from 70 to mid value:
Z = (70 - 100)/10 = -3
Case 2:
For X from mid value to 130:
Z = (130 - 100)/10 = 3
By Empirical Rule, 99.7 % of data falls within three standard deviations from the mean.
So,
Answer is:
99.7 %
(b)
To find P(X < 90 OR X > 100):
Case 1:
For X < 90:
Z = (90 - 100)/10 = = - 1
Case 2:
For X > 110:
Z = (110 - 100)/10 = 1
By Emprical Rlule, 68.27 % of data falls within the first standard deviation from the mean.
So,
Percentage of dta not within the first standard deviation from the mean = 100 - 68.27 = 31.73 %
So,
Answer is:
31.73 %
(c)
To find P(X>120):
z + (120 - 100)/10 = 2
By empirical rule, 95.44 % fall within two standard deviations.
Since here only the upper side is required, Percentage of people having greater than 120 is got as follows:
95.44/2 = 47.72
So,
P(X>120) = 50 - 47.72 = 2.28
So,
Answer is:
2.28 %