Question

Need Linear Regression Analysis done for the following data:

Day	BP Diastolic	Ate Healthy and Exercised
1	85	N
2	109	N
3	96	N
4	92	N
5	99	N
6	98	N
7	102	Y
8	93	N
9	90	Y
10	84	N
11	90	N
12	86	N
13	81	N
14	77	Y
15	90	Y
16	86	Y
17	83	N
18	80	Y
19	78	N
20	74	Y
21	72	Y
22	79	Y
23	84	Y
24	91	Y
25	85	Y
26	77	Y
27	78	Y
28	81	N
29	88	Y
30	85	Y
31	77	Y
32	74	Y
33	72	Y
34	77	N
35	80	Y
36	81	Y
37	76	Y
38	78	Y
39	72	Y
40	73	Y
41	72	Y
42	79	Y
43	80	Y
44	84	Y
45	81	Y
46	78	Y
47	71	Y
48	73	Y
49	76	Y
50	75	Y
51	76	N
52	81	Y
53	78	N
54	75	Y
55	77	Y
56	76	Y

Answer 1

Let us consider BP Diastolic(Y) is dependent variable and Ate Healthy and Exercised(X) is independent varaible

Ate Healthy and Exercised(X) :

If X = 1, Ate Healthy and Exercised (Yes)

X = 0, Do not ate Healthy and Exercised (No)

SUMMARY OUTPUT
Regression Statistics
Multiple R	0.44587202
R Square	0.198801858
Adjusted R Square	0.183964856
Standard Error	7.473174191
Observations	56
ANOVA
	df	SS	MS	F	Significance F
Regression	1	748.3150452	748.3150452	13.39905798	0.000573317
Residual	54	3015.809955	55.8483325
Total	55	3764.125
	Coefficients	Standard Error	t Stat	P-value	Lower 95%	Upper 95%	Lower 95.0%	Upper 95.0%
Intercept	87.41176471	1.812510974	48.22688854	4.43011E-46	83.777899	91.04563042	83.777899	91.04563042
Ate Healthy and Exercised(X)	-7.950226244	2.171912649	-3.660472371	0.000573317	-12.30464893	-3.595803559	-12.30464893	-3.595803559

BP Diastolic(Y) = 87.4118 - 7.9502 * Ate Healthy and Exercised(X)

R^2 = 0.1988,

19.88% of variation in Y variable is explained by variation in X variable

If X = 1, Ate Healthy and Exercised (Yes)

BP Diastolic(Y) = 87.4118 - 7.9502 * 1 = 79.4616

X = 0, Do not ate Healthy and Exercised (No)

BP Diastolic(Y) = 87.4118 - 7.9502 * 0 = 87.4118