Question
In: Statistics and Probability
An advertiser who is planning a radio campaign is interested in the number of minutes of...
An advertiser who is planning a radio campaign is interested in the number of minutes of music played per hour by five local radio stations. A sample of 5 hours is taken from each station. Complete the following analysis, using the information given, and using a 0.05 level of significance. For full marks your answer should be accurate to at least two decimal places. Sample means FM 92 FM 97 FM 101 FM 104 FM 107 50.6 51.4 44.6 48.8 51.6 a) Complete the following ANOVA table: b) Calculate the critical value: c) Is there a difference in the treatment means? Yes, because the test statistic is greater than the critical value Yes, because the test statistic is less than the critical value No, because the test statistic is greater than the critical value No, because the test statistic is less than the critical value
Solutions
orchestra answered 1 year agoRelated Solutions
An advertiser who is planning a radio campaign is interested in the number of minutes of...
An advertiser who is planning a radio campaign is interested in
the number of minutes of music played per hour by five local radio
stations. A sample of 4 hours is taken from each station. Complete
the following analysis, using the information given, and using a
0.05 level of significance.
For full marks your answer should be accurate to at least two
decimal places.
Sample means
FM 92
FM 97
FM 101
FM 104
FM 107
50
46.5
53.25
48.5...
Top Toys is planning a new radio and TV advertising campaign. A radio commerical costs $300...
Top Toys is planning a new radio and TV advertising campaign. A
radio commerical costs $300 and a TV ad costs $2000. A total budget
of $20,000 is allocated to the campaign. However, to ensure that
each medium will have at least one radio commercial and one TV ad,
the most that can be allocated to either medium cannot exceed 80%
of the total budget. It is estimated that the first radio
commerical will reach 5000 people, with each additional...
FIRMCo is planning an advertising campaign, budgeted at $70000. Each 1000 dollars spent on radio ads,...
FIRMCo is planning an advertising campaign, budgeted at $70000.
Each 1000 dollars spent on radio ads, results in 70 new customers.
Similarly, each 1000 dollars spent on TV ads yield 105 new
customers. Each radio ad costs $250, and each TV ad costs $1500.
The combined number of ads used in the campaign cannot exceed 75.
The amount spent on radio ads, and the amount spent on TV ads
cannot differ from one another by more than $15000. Define the...
.As a political scientist, you are interested in evaluating the average number of campaign stops that...
.As a political scientist, you are interested in evaluating the
average number of campaign stops
that Senate candidates make per week during the general election
campaign. Previous research
on the subject suggests that the average number of campaign stops
per weeks is equal to 26
(conventional wisdom). You are interested in testing this against
the possibility that this is not
the parameter value (two-tailed test). You collect a sample of n =
20 candidates, and find a
sample mean of...
A researcher is interested in finding a 95% confidence interval for the mean number minutes students...
A researcher is interested in finding a 95% confidence interval
for the mean number minutes students are concentrating on their
professor during a one hour statistics lecture. The study included
41 students who averaged 34.7 minutes concentrating on their
professor during the hour lecture. The standard deviation was 12.1
minutes. Round answers to 3 decimal places where possible.
a. To compute the confidence interval use a distribution.
b. With 95% confidence the population mean minutes of
concentration is between and...
An educational organization in California is interested in estimating the mean number of minutes per day...
An educational organization in California is interested in
estimating the mean number of minutes per day that children between
the age of 6 and 18 spend watching television per day. A previous
study showed that the population standard deviation was 21.5
minutes. The organization selected a random sample of n = 251
children and recorded the number of minutes of TV that each person
watched on a particular day. The mean time was 171.3 minutes. If
the leaders of the...
A researcher is interested in finding a 90% confidence interval for the mean number minutes students...
A researcher is interested in finding a 90% confidence interval
for the mean number minutes students are concentrating on their
professor during a one hour statistics lecture. The study included
128 students who averaged 42.3 minutes concentrating on their
professor during the hour lecture. The standard deviation was 10.7
minutes. Round answers to 3 decimal places where possible.
a. To compute the confidence interval use a _____ (t? or z?)
distribution.
b. With 90% confidence the population mean minutes of...
A researcher is interested in finding a 95% confidence interval for the mean number minutes students...
A researcher is interested in finding a 95% confidence interval
for the mean number minutes students are concentrating on their
professor during a one hour statistics lecture. The study included
133 students who averaged 41.3 minutes concentrating on their
professor during the hour lecture. The standard deviation was 13.3
minutes. Round answers to 3 decimal places where possible.
a. To compute the confidence interval use a ? t
z distribution.
b. With 95% confidence the population mean minutes of
concentration is...
A researcher is interested in finding a 99% confidence interval for the mean number minutes students...
A researcher is interested in finding a 99% confidence interval
for the mean number minutes students are concentrating on their
professor during a one hour statistics lecture. The study included
105 students who averaged 38.1 minutes concentrating on their
professor during the hour lecture. The standard deviation was 11.2
minutes. Round answers to 3 decimal places where possible.
a. To compute the confidence interval use a ? z
t distribution.
b. With 99% confidence the population mean minutes of
concentration is...
To compare the effectiveness of a media campaign - via radio ads, billboards, and ads on...
To compare the effectiveness of a media campaign - via radio
ads, billboards, and ads on social media websites - to reduce the
incidence of impaired driving, a police chief inspected data from
60 randomly chosen CheckStops at varying locations.Thirty of these
were before the launch of this campaign, 30 were after the media
campaign had been running for a months time. Use α=0.05α=0.05 for
all calculations.
For each CheckStop randomly chosen, the number of people charged
with impaired driving...
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