In: Advanced Math
What is the probability getting a license plate that has a repeated letter or digit if you live in a state in which license plate have two letters followed by four numerals?
Solution :
Now to answer this question we first calculate the total number of license plate possible with the given condition .
So given in the state license plate have two letters followed by four numerals .
So there are 6 positions in a license plate that have two letters followed by four numerals .
Now each of these 2 letters can be any of 26 letters , similarly each of these 4 digits can be any of 10 numerals .
So for any random license in the state it's 6 position can be occupied in the following ways :
1st position : have 26 choices ( 26 letters of alphabet )
2nd position : have 26 choices ( 26 letters of alphabet )
3rd position : have 10 choices (10 digits of numerals )
4th position : have 10 choices ( 10 digits of numerals )
5th position : have 10 choices (10 digits of numerals )
6th position : have 10 choices ( 10 digits of numerals )
So by multiplication principle :
the total number of license plate possible in the state which have two letters followed by four numerals are :
Now we wish to calculate probability of getting a license plate that has a repeated letter or digit .
Now complement of this event is :
calculating probability of getting a license plate that do not have any repeated letter or any repeated digit .
And we know
So
probability of getting a license plate that has a repeated letter or digit
probability of getting a license plate that do not have any repeated letter or any repeated digit .
So let us calculate total number of license plate possible that do not have any repeated letter or digit
So there are 6 positions in a license plate that have two letters followed by four numerals .
we don't want any repeated letter or any repeated digit . .
So here in this case 6 position can be occupied in the following ways :
1st position : have 26 choices ( 26 letters of alphabet )
2nd position : have 25 choices ( because we have used 1 of the letter in 1st position and letters cannot be repeated , hence we are left with remaining 25 letters of alphabet )
3rd position : have 10 choices (10 digits of numerals )
4th position : have 9 choices ( because we have used 1 of the numerals in 3rd position and digits cannot be repeated , hence we are left with remaining 9 numerals )
5th position : have 8 choices ( because we have used 2 numerals in 3rd and 4th position )
6th position : have 7 choices ( because we have used 3 numerals in 3rd , 4th and 5th position )
So by multiplication principle :
the total number of license plate possible that do not have any repeated letter or any repeated digit are :
Therefore we get probability of getting a license plate that do not have any repeated letter or digit . as :
So probability of getting a license plate that do not have any repeated letter or any repeated digit . is :
Hence
probability of getting a license plate that has a repeated letter or digit
probability of getting a license plate that do not have any repeated letter or digit .
probability of getting a license plate that has a repeated letter or digit
.............. ( rounded to one decimal place )
Therefore answer is :
the probability getting a license plate that has a repeated letter or digit if you live in a state in which license plate have two letters followed by four numerals is :