In: Statistics and Probability
A study group is to be selected from 5 freshmen, 7 sophomores, and 4 juniors. a. If a study group is to consist of 4 freshmen, 6 sophomores, and 2 juniors, how many different ways can the study group be selected? b. If a study group consisting of 6 students is selected, what is the probability that the group will consist of 2 freshmen, 3 sophomores, and 1 junior?
Solution:
Given:
A study group is to be selected from:
5 freshmen,
7 sophomores, and
4 juniors
Total = 16
Part a) how many different ways can the study group be selected if a study group is to consist of:
4 freshmen, 6 sophomores, and 2 juniors
4 freshmen from 5 freshmen can be selected in 5C4 ways
6 sophomores from 7 sophomores can be selected in 7C6 ways
and
2 juniors from 4 juniors can be selected in 4C2 ways
Thus
Total number of Ways = 5C4 X 7C6 X 4C2
Use following combination formula:
Thus
Total number of Ways = 5C4 X 7C6 X 4C2
Total number of Ways =5 X 7 X 6
Total number of Ways = 210
Part b) Find:
the probability that the group will consist of 2 freshmen, 3 sophomores, and 1 junior if a study group consisting of 6 students.
P( 2 freshmen, 3 sophomores, and 1 junior) =.........?
P( 2 freshmen, 3 sophomores, and 1 junior) = [ 5C2 X 7C3 X 4C1 ] / [ 16C6 ]
and
Thus
P( 2 freshmen, 3 sophomores, and 1 junior) = [ 5C2 X 7C3 X 4C1 ] / [ 16C6 ]
P( 2 freshmen, 3 sophomores, and 1 junior) = [ 10 X 35 X 4 ] / [ 8008 ]
P( 2 freshmen, 3 sophomores, and 1 junior) = 1400 / 8008
P( 2 freshmen, 3 sophomores, and 1 junior) = 0.174825
P( 2 freshmen, 3 sophomores, and 1 junior) = 0.1748