In: Statistics and Probability
When playing roulette at a casino, a gambler is trying to decide whether to bet $15 on the number 28 or to bet $15 that the outcome is any one of the three possibilities 00 comma 0 comma or 1. The gambler knows that the expected value of the $15 bet for a single number is negative $ 1.58. For the $15 bet that the outcome is 00 comma 0 comma or 1, there is a probability of StartFraction 3 Over 38 EndFraction of making a net profit of $45 and a StartFraction 35 Over 38 EndFraction probability of losing $15.
a. Find the expected value for the $15 bet that the outcome is 00 comma 0 comma or 1.
b. Which bet is better: a $15 bet on the number 28 or a $15 bet that the outcome is any one of the numbers 00 comma 0 comma or 1? Why?
We have been given that the expected value of the $15 bet for a single number is -$1.58.
Hence, the expected value of betting $15 on number 28 is -$1.58
a) Let Y be the net profit when bet $15 the outcome is 00,0, or 1.
For the $15 bet that the outcome is 00,0, or 1, there is a probability of 3/38 of making a net profit of $45 and a 35/38 probability of losing $15.
The probability distribution of Y is
y | P(y) |
45 | 3/38 |
-15 | 35/38 |
The expected value of Y is
ans: the expected value for the $15 bet that the outcome is 00,0, or 1 is -$10.26
b) We can see that the expected value of $15 bet on number 28 is higher (of lower negative value), that the expected value for the $15 bet that the outcome is 00,0, or 1. We chose the bet with higher payoff (or lower loss)
ans: a $15 bet on the number 28 is better as it has a higher expected value (or has a lower expected loss).