Question
In: Statistics and Probability
In a survey of a group of men, the heights in the 20-29 age group were...
In a survey of a group of men, the heights in the 20-29 age group were normally distributed, with a mean of
69.6 inches and a standard deviation of 2.0 inches. A study participant is randomly selected. a) Find a probability that a study participant has a height that is less than 66 inches. b) Find the probability that a study participant has a height that is between 66 and 72. c) Find the probability that a study participant has a height that is more than 72 inches. d)
inches.
Solutions
Expert Solution
Let "X" be the men's height.
Refer Standard normal table/Z-table to find the probability or use excel formula "=NORM.S.DIST(-1.80, TRUE)" to find the probability.
The probability that a study participant has a height that is
less than 66 inches is 
.
------------------------------------------------------------------------------------------------
Note: P(a<Z<b)=P(Z<b)-P(Z<a)
Refer Standard normal table/Z-table to find the probability or use excel formula "=NORM.S.DIST(1.20, TRUE)" & "=NORM.S.DIST(-1.80, TRUE)" to find the probability.
The probability that a study participant has a height
that is between 66 and 72 
------------------------------------------------------------------------------------------------
Note: P(Z>a)=1-P(Z<a)
Refer Standard normal table/Z-table to find the probability or use excel formula "=NORM.S.DIST(1.20, TRUE)" to find the probability.
The probability that a study participant has a height that is
more than 72 inches is 
.
------------------------------------------------------------------------------------------------
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