In: Statistics and Probability
Problem 16-01 (Algorithmic)
The management of Brinkley Corporation is interested in using simulation to estimate the profit per unit for a new product. The selling price for the product will be $45 per unit. Probability distributions for the purchase cost, the labor cost, and the transportation cost are estimated as follows:
Procurement Cost ($) |
Probability |
Labor Cost ($) |
Probability |
Transportation Cost ($) |
Probability |
10 | 0.35 | 20 | 0.2 | 3 | 0.72 |
11 | 0.25 | 23 | 0.25 | 5 | 0.28 |
13 | 0.4 | 24 | 0.35 | ||
26 | 0.2 |
SOLUTION:
a).Base-case is the maximum probability
case.
Profit per unit for base-case = selling price - procurement cost -
labor cost - transportation cost
= 45 - 13 - 24 - 3 = $5
Profit per unit for the worst-case = 45-13-26-5 = $ 1
Profit per unit for the best-case = 45-10-20-3 = $ 12
b) Simulation model is following:
Procurement cost($) | Probability | RN Range |
10 | 0.35 | 0.00 |
11 | 0.25 | 0.35 |
13 | 0.40 | 0. |
Labor cost($) | Probability | RN Range |
20 | 0.20 | 0.00 |
23 | 0.25 | 0.20 |
24 | 0.35 | 0.45 |
26 | 0.20 | 0.80 |
Rransportation cost($) | Probability | RN Range |
3 | 0.72 | 0.00 |
5 | 0.28 | 0.72 |
SIMULATIOM:
Trial | Procurement cost | Labor cost | Transportation cost | Profit per unit |
1 | 13 | 23 | 3 | 6 |
2 | 10 | 20 | 5 | 10 |
3 | 11 | 23 | 3 | 8 |
4 | 13 | 24 | 3 | 5 |
5 | 13 | 23 | 5 | 4 |
6 | 11 | 24 | 3 | 7 |
7 | 13 | 23 | 3 | 6 |
8 | 13 | 24 | 5 | 3 |
9 | 11 | 24 | 3 | 7 |
10 | 10 | 20 | 3 | 12 |
11 | 13 | 23 | 5 | 4 |
12 | 11 | 20 | 5 | 9 |
13 | 13 | 20 | 3 | 9 |
14 | 10 | 20 | 5 | 10 |
15 | 10 | 23 | 3 | 9 |
Mean profit per unit = 0.436
Probability that the mean profit per unit will be less than $ 4 = 0.136.
EXCEL formulas for simulation table:
Trial | Procurement cost | Labor cost | Transportation cost | Profit per unit |
1 | LOOKUP(RAND(),$C$2:$C$4,$A$2:$A$4) | =LOOKUP(RAND(),$G$2:$G$5,$E$2:$E$5) | =LOOKUP(RAND(),$K$2:$K$3,$I$2:$I$3) | =$B$6-SUM(B10:D10) |
2 | LOOKUP(RAND(),$C$2:$C$4,$A$2:$A$4) | =LOOKUP(RAND(),$G$2:$G$5,$E$2:$E$5) | =LOOKUP(RAND(),$K$2:$K$3,$I$2:$I$3) | =$B$6-SUM(B11:D11) |
3 | LOOKUP(RAND(),$C$2:$C$4,$A$2:$A$4) | =LOOKUP(RAND(),$G$2:$G$5,$E$2:$E$5) | =LOOKUP(RAND(),$K$2:$K$3,$I$2:$I$3) | =$B$6-SUM(B12:D12) |
Copy these formulas down SD 500 rows for 500 simulation trials.
Formula for mean profit (cell 110) =AVERAGE(E10:E509)
Formula for Probability that the mean profit per unit will be Is
than $ 4 =COUNTIF(E10:E509," <"&4)/COUNT(E10:E509)
Mean profit per unit = $ 6.616
c)
Simulation approach is better than generating a variety of what-if
scenarios, because there are 24 different possible combinations
(3*4*2=24) of procurement, labor and transportation cost. So, 24
different what-if scenarios are required to generate all the
possible profit. What-if scenarios do not account for the
probability just as they happen in real life.
On the other hand, simulation does not require 24 different models,
just one model is needed and it accounts for the probability, just
it happens in real life. Hence simulation is better than generating
a variety of what-if scenarios.
d)
Probability that the mean profit per unit will be less than $ 4 =
0.136
[the answers based on simulation will not match exactly with any
answer key]
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