6a. A compound is analyzed and is found to be composed of 36.93% carbon, 4.65% hydrogen,...

6a. A compound is analyzed and is found to be composed of 36.93% carbon, 4.65% hydrogen, and 58.42% fluorine. What is the empirical formula of this compound? (10 pts)

6b. If the molar mass of the compound described above is approximately195 g/mol, what is the molecular formula of the compound? (2 pts)

Solutions

Expert Solution

Empirical Formula of the Compound will be : C2H3F2

Molecular formula of the compound will be : C6H9F6

First we will find out moles of each atom.

Number of moles = Given Mass / Atomic mass

Then we will find out relative moles and their simplest whole number ratio.

This will gives us Empirical formula.

To find molecular formula , first we will find out n ( a whole number)

n= Molecular mass / Empirical formula mass .

At last : Molecular formula = n × Empirical formula.

For detailed work, please go through the images .

queen_honey_blossom answered 1 year ago

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