In: Chemistry
6a. A compound is analyzed and is found to be composed of 36.93% carbon, 4.65% hydrogen, and 58.42% fluorine. What is the empirical formula of this compound? (10 pts)
6b. If the molar mass of the compound described above is approximately195 g/mol, what is the molecular formula of the compound? (2 pts)
Empirical Formula of the Compound will be : C2H3F2
Molecular formula of the compound will be : C6H9F6
First we will find out moles of each atom.
Number of moles = Given Mass / Atomic mass
Then we will find out relative moles and their simplest whole number ratio.
This will gives us Empirical formula.
To find molecular formula , first we will find out n ( a whole number)
n= Molecular mass / Empirical formula mass .
At last : Molecular formula = n × Empirical formula.
For detailed work, please go through the images .