Question

In: Statistics and Probability

In a recent survey of 200 Instagram users, it was found that 71% of them were...

In a recent survey of 200 Instagram users, it was found that 71% of them were under the age of 35. Create and interpret a 95% Confidence Interval for the percentage of Instagram under the age of 35 using PANIC.

Solutions

Expert Solution

Solution :

Given that,

n =200

Point estimate = sample proportion = = 0.71

1 -   = 1- 0.71 =0.29

At 95% confidence level the z is ,

= 1 - 95% = 1 - 0.95 = 0.05

/ 2 = 0.05 / 2 = 0.025

Z/2 = Z0.025 = 1.96   ( Using z table )

Margin of error = E = Z / 2    * ((( * (1 - )) / n)

= 1.96 (((0.71*0.29) /200 )

= 0.0629

A 95% confidence interval for population proportion p is ,

- E < p < + E

0.71-0.0629 < p <0.71+ 0.0629

0.6471< p < 0.7729

The 95% confidence interval for the population proportion p is : 0.6471, 0.7729

orchestra answered 1 year ago
Next > < Previous

Related Solutions

In a survey of 145 students at GCSC it was found that 47 of them were...
In a survey of 145 students at GCSC it was found that 47 of them were enrolled in the course Mathematics for the Liberal Arts. If two students from this survey were randomly chosen without replacement, what is the probability at least one of them is enrolled in the courseMathematics for the Liberal Arts? Round your answer to 4 decimal places. (Hint: The complement of "at least one" is "none". Find the probability that neither of the two people chosen...
A survey of 200 drivers who were at fault in an accident found that 62% were...
A survey of 200 drivers who were at fault in an accident found that 62% were dropped by their insurance carrier. Conduct a hypothesis test at a 0.10 level of significance to determine if the percentage of drivers dropped by the insurance carrier is different than 60%. State the null and alternate hypotheses. Please show work
A survey of 200 drivers who were at fault in an accident found that 62% were...
A survey of 200 drivers who were at fault in an accident found that 62% were dropped by their insurance carrier. Conduct a hypothesis test at a 0.10 level of significance to determine if the percentage of drivers dropped by the insurance carrier is different than 60%. State the null and alternate hypotheses. Use whichever applicable approach to hypothesis testing that you prefer, specify the numerical comparisons to be made, and state your conclusion.
Out of 200 people surveyed, 70 of them were found to be in favor of changing...
Out of 200 people surveyed, 70 of them were found to be in favor of changing the color of the five dollar bill from green to purple. Give a 99% confidence interval for the proportion of people in favor of changing the color of the five dollar bill.
A recent survey of 1050 employees found that 24​% of them would lay off their bosses...
A recent survey of 1050 employees found that 24​% of them would lay off their bosses if they could. Complete parts a through d below based on a random sample of 10 employees. A.) What is the probability that exactly three employees would lay off their​ boss? B.) What is the probability that three or fewer employees would lay off their​ bosses? C.)What is the probability that five or more employees would lay off their​ bosses? D.) What are the...
A recent survey of 1016 employees found that 29​% of them would lay off their bosses...
A recent survey of 1016 employees found that 29​% of them would lay off their bosses if they could. Complete parts a through d below based on a random sample of 10 employees. a. What is the probability that exactly three employees would lay off their​ boss? The probability is b. What is the probability that three or fewer employees would lay off their​ bosses? c. What is the probability that five or more employees would lay off their​ bosses?...
A recent survey of 1012 employees found that 24% of them would lay off their bosses...
A recent survey of 1012 employees found that 24% of them would lay off their bosses if they could. Complete parts A through D below based on a random sample of 10 employees. A) What is the probability that exactly three employees would lay off their​ boss? B) What is the probability that three or fewer employees would lay off their​ bosses? C). What is the probability that five or more employees would lay off their​ bosses? D) What are...
A social media survey found that 71% of parents are​ "friends" with their children on a...
A social media survey found that 71% of parents are​ "friends" with their children on a certain online networking site. A random sample of 140 parents was selected. Complete parts a through d below. a. Calculate the standard error of the proportion. sigma Subscript p equals0.0383 ​(Round to four decimal places as​ needed.) b. What is the probability that 105 or more parents from this sample are​ "friends" with their children on this online networking​ site? ​P(105 or more parents...
A survey questioned 1,000 men. The survey revealed that 71% of them have visited Disney World...
A survey questioned 1,000 men. The survey revealed that 71% of them have visited Disney World before. Of those who have visited Disney World before, 61% have children. Of those who never visited Disney World before, 68% don't have children. What is the probability that a man selected at random has children? a) 0.3200 b) 0.6100 c) 0.5259 d) 0.9300 e) 0.0512 f) None of the above.
A study of 420,042 cell phone users found that 130 of them developed cancer of the...
A study of 420,042 cell phone users found that 130 of them developed cancer of the brain or nervous system. Prior to this study of cell phone​ use, the rate of such cancer was found to be 0.0323​% for those not using cell phones. Complete parts​ (a) and​ (b). a. Use the sample data to construct a 95​% confidence interval estimate of the percentage of cell phone users who develop cancer of the brain or nervous system. a. __% <...
ADVERTISEMENT
Subjects
ADVERTISEMENT
Latest Questions
ADVERTISEMENT