In: Statistics and Probability
Solution:
Find the total area under the standard normal curve to the left of z = -0.22 or to the right of z = 1.17.
That is:
P( Z < -0.22 or Z > 1.17) =..........?
P( Z < -0.22 or Z > 1.17) = P( Z < -0.22) + P(Z > 1.17)
P( Z < -0.22 or Z > 1.17) = P( Z < -0.22) + [ 1 - P(Z < 1.17) ]
Look in z table for z = -0.2 and 0.02 as well as for z = 1.1 and 0.07 and find corresponding area.
P( Z< -0.22) = 0.4129
and
P( Z< 1.17) = 0.8790
thus
P( Z < -0.22 or Z > 1.17) = P( Z < -0.22) + [ 1 - P(Z < 1.17) ]
P( Z < -0.22 or Z > 1.17) = 0.4129 + [ 1 - 0.8790 ]
P( Z < -0.22 or Z > 1.17) = 0.4129 + 0.1210
P( Z < -0.22 or Z > 1.17) = 0.5339
Thus the total area under the standard normal curve to the left of z = -0.22 or to the right of z = 1.17 is 0.5339