Question

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Aluminum is a reactive metal. It reacts with oxygen to form aluminum oxide as shown below....

Aluminum is a reactive metal. It reacts with oxygen to form aluminum oxide as shown below.

4 Al(s) + 3 O (g) → 2 Al O (s)

I. When one mole of aluminum reacts with excess oxygen how many moles of aluminum oxide will be produced? II. When one mole of oxygen reacts with excess aluminum how many moles of aluminum oxide will be produced? III. When one mole of aluminum reacts with one mole of oxygen how many moles of aluminum oxide will be produced?

Solutions

Expert Solution

4 Al (s) + 3 O2 (g) ------------> 2 Al2O3 (s)

I. When one mole of aluminum reacts with excess oxygen how many moles of aluminum oxide will be produced?

        4 Al (s) + 3 O2 (g) ------------> 2 Al2O3 (s)

         4              3                                 2

         1                                                ?

moles of aluminum oxide formed = 1 x 2 / 4 = 1/2

                                                        = 0.5

II. When one mole of oxygen reacts with excess aluminum how many moles of aluminum oxide will be produced?

4 Al (s) + 3 O2 (g) ------------> 2 Al2O3 (s)

         4              3                                 2

                         1                                ?

moles of aluminum oxide formed = 1 x 2 / 3

                                                        = 0.67

III. When one mole of aluminum reacts with one mole of oxygen how many moles of aluminum oxide will be produced?

     4 Al (s) + 3 O2 (g) ------------> 2 Al2O3 (s)

         4              3                                 2

       1               1

limiting reagent is Al . so product based on Al

moles of aluminum oxide formed = 1 x 2 / 4 = 1/2

                                                        = 0.5

queen_honey_blossom answered 1 year ago
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