In: Statistics and Probability
Business Weekly conducted a survey of graduates from 30 top MBA
programs. On the basis of the survey, assume the mean annual salary
for graduates 10 years after graduation is 167000 dollars. Assume
the standard deviation is 32000 dollars. Suppose you take a simple
random sample of 100 graduates.
Find the probability that a single randomly selected salary is more
than 162000 dollars.
P(X > 162000) = _______
Find the probability that a sample of size n=100 is randomly
selected with a mean that is more than 162000 dollars.
P(M > 162000) = _________
Enter your answers as numbers accurate to 4 decimal places.
Solution :
Given that ,
mean = = 167000
standard deviation = = 32000
P(x > 162000) = 1 - P(x < 162000)
= 1 - P[(x - ) / < (162000 - 167000) / 32000)
= 1 - P(z < -0.1563)
= 1 - 0.4379
= 0.5621
P(x > 162000) = 0.5621
n = 100
M = 167000
M = / n = 32000 / 100 = 3200
P(M > 162000) = 1 - P( < 162000)
= 1 - P[(M - M) / M < (162000 - 167000) / 3200]
= 1 - P(z < -1.5625)
= 1 - 0.0591
= 0.9409
P(M > 162000) = 0.9409