Find the double integral of region (2x-y)dA, where region R is in the first quadrant enclosed...

Find the double integral of region (2x-y)dA, where region R is in the first quadrant enclosed by the circle x²+y²=4 and the lines x=0 and y=x

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Expert Solution

I = SJ (2x-4) dA Solutioy : Let R: x² + y2 = 4 x=0,yan 2 ostyan x = 0 pey²4 (2,0) 310 I polar co-ordinatus put nar caso Yarsino then x² + y² = 82 - 8=2 and dA = dydx = r dodo Samo = o caso tano - I o = 1 thus vo T/2 . I. S (x 6030 - XSine) . x de do som k (916 - sho) (* do ce nter som le 940 - Suo)de 0 . Ja 64 1174 24 (2+0 - er 12- ] = -2.5882

milcah answered 1 year ago

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