Question
In: Mechanical Engineering
A rivet is to be inserted into a hole. A random sample of n equals 15...
A rivet is to be inserted into a hole. A random sample of n equals 15 parts is selected and the hole diameter is measured. The sample standard deviation is millimeters. Is there strong evidence to indicate that the standard deviation of hole diameter exceeds 0.01 millimeters? Use (a) Calculate the test statistic Round your answer to two decimal places (e.g. 98.76). (b) Is there strong evidence to indicate that the standard deviation of hole diameter exceeds 0.01 millimeters?
Solutions
samet mamat answered 2 years agoRelated Solutions
A rivet is to be inserted into a hole. A random sample n=15 of parts is...
A rivet is to be inserted into a hole. A random sample n=15 of
parts is selected, and the hole diameter is measured. The sample
standard deviation of the hole diameter measurements is s=0.008
millimeters. Construct a 99% lower confidence bound for σ2 using
MATLAB step by step . Please screenshot the MATLAB screen
2. A rivet is to be inserted into a hole. If the standard deviation of hole...
2. A rivet is to be inserted into a hole. If the
standard deviation of hole diameter exceeds 0.02 mm, there is an
unacceptably high probability that the rivet will not fit. A random
sample of n = 15 parts is selected, and the hole diameter is
measured. The sample standard deviation of the hole diameter
measurements is s = 0.016mm. At α = 0.05 conduct a hypothesis test
to investigate to indicate that the standard deviation of hole
diameter...
A simple random sample of size n equals n=40 is drawn from a population. The sample...
A simple random sample of size
n equals n=40
is drawn from a population. The sample mean is found to be
x overbar equals 120.3
and the sample standard deviation is found to be
s equals 12.3
Construct a 99% confidence interval for the population
mean.
A simple random sample of size n equals n=40 is drawn from a population. The sample...
A simple random sample of size
n equals n=40
is drawn from a population. The sample mean is found to be
x overbar equals x=120.1
and the sample standard deviation is found to be
s equals s=12.5.
Construct a 99% confidence interval for the population
mean.
The lower bound is:
The upper bound is:
*ANSWERS FOR TI 84 CALC
A simple random sample of size n equals 40 is drawn from apopulation. The sample...
A simple random sample of size n equals 40 is drawn from a
population. The sample mean is found to be x overbar equals 121.3
and the sample standard deviation is found to be s equals 12.9.
Construct a 99% confidence interval for the population mean.
Upper:
Lower:
A simple random sample of size n equals 40 is drawn from a population. The sample...
A simple random sample of size n equals 40 is drawn from a
population. The sample mean is found to be x overbar equals 121.9
and the sample standard deviation is found to be s equals 12.9.
Construct a 99% confidence interval for the population mean.
Lower bound:
Upper bound:
A simple random sample of size n equals 40n=40 is drawn from a population. The sample...
A simple random sample of size
n equals 40n=40
is drawn from a population. The sample mean is found to be
x overbar equals 121.1x=121.1
and the sample standard deviation is found to be
s equals 12.7s=12.7.
Construct a 99% confidence interval for the population
mean.
The lower bound is..
the upper bound is..
A simple random sample of size n equals 18 is drawn from a population that is...
A simple random sample of size n equals 18 is drawn from a
population that is normally distributed. The sample mean is found
to be x overbar equals 62 and the sample standard deviation is
found to be s equals 20. Construct a 95% confidence interval about
the population mean.
A simple random sample of size n equals 16 is drawn from a population that is...
A simple random sample of size
n equals 16
is drawn from a population that is normally distributed. The
sample variance is found to be
13.7
Test whether the population variance is greater than
10
at the
alpha equals 0.05
level of significance.
I only need to find the test statistic and the p-value. Would
you go through it step by step please.
A simple random sample of size n equals n=400 individuals who are currently employed is asked...
A simple random sample of size n equals n=400 individuals who
are currently employed is asked if they work at home at least once
per week. Of the 400 employed individuals surveyed, 40 responded
that they did work at home at least once per week. Construct a 99%
confidence interval for the population proportion of employed
individuals who work at home at least once per week.
ADVERTISEMENT
ADVERTISEMENT
Latest Questions
- Froya Fabrikker A/S of Bergen, Norway, is a small company that manufactures specialty heavy equipment for...
- When the electricity goes out on your campus, a backup source powers the servers that handle...
- I am having trouble with my assignment and getting compile errors on the following code. The...
- Can someone show me how to write a Haskell function using snd on a list of...
- Please do in java Program 3: Give a baby $5,000! Did you know that, over the...
- This is all one question, thank you so much in advance! You must evaluate the purchase...
- 10. Consider a market in which there is a monopoly manufacturer and a mo nopoly retailer....
ADVERTISEMENT