Question

In: Biology

The ‘blue baby’ syndrome results from (a) excess of TDS (total dissolved solids) (b) excess of...

The ‘blue baby’ syndrome results from

(a) excess of TDS (total dissolved solids)

(b) excess of chloride

(c) methaemoglobin

(d) excess of dissolved oxygen

Solutions

Expert Solution

ANSWER : METHAEMOGLOBIN

EXPLANANTION : Blue Baby Syndrome or Methemoglobinemia is caused by decreased ability of blood to carry oxygen, resulting in oxygen deficiency in different body parts.

The blue baby syndrome shows an incomplete wall between the ventricles (known as a ventricular septal defect), an aorta that sits over this defect so that its blood comes from both ventricles instead of just from the left (overriding aorta), a defective right ventricular outflow tract near the pulmonary valve that prevents full flow of blood to the lungs, a muscular right ventricle necessary to complete the extra work required to overcome that defect (right ventricular hypertrophy). ( SEE DIAGRAM)

Nitrate itself is not toxic to humans. Nitrate becomes a problem only when it is converted to nitrite in the human body, resulting in methemoglobinemia. Much of the ingested nitrate is absorbed before reaching the nitrate-reducing bacteria, which resides in the intestinal tract. Most of the ingested nitrate is excreted within 24 hours mainly through urine, as well as through feces and sweat. If nitrate is introduced directly into the colon, methemoglobinemia is readily produced. Nitrite produced from nitrate enters the bloodstream mainly through the upper gastrointestinal tract. Nitrate is converted to nitrite by intestinal bacteria, and nitrite acts as the oxidizing agent to form METHAEMOGLOBIN in the red blood cells.

DIAGRAM

  


Related Solutions

Calculate the mass in mg of the following solutes (total dissolved solids or the elements indicated):...
Calculate the mass in mg of the following solutes (total dissolved solids or the elements indicated): A. 425 mL of an acid solution containing 3.17 ppm of U2O3 (1ppm = 1mg/L) B. 12.75 mL of a 6.24 x 10^-3 M Pb(NO3)2 solution C. 37.5 mL of 0.0125 M KBrO3 (mromine mass only) D. 0.750 mL of 0.0455 M AgNO3 (siliver only) Please show work so that i can understand thanks
GC Analysis a) is best done on solids dissolved in a volatile solvent b) on neat...
GC Analysis a) is best done on solids dissolved in a volatile solvent b) on neat high melting solids c) on neat volatile liquids or solids d) none of the above I just want to see if my reasoning is correct and if not, why: it would be a) because the GC will recognize the solid in solution as a disruption in the gas more easily than b or c.
Two Einstein solids A and B have 10 and 4 oscillators res[pectively ad a total of...
Two Einstein solids A and B have 10 and 4 oscillators res[pectively ad a total of 10 units of energy. a) How many macrostates are there, b How many microstates for the combined system? c) What is the most likely macrostate d) What is the probability of finding all energy in solid A?
Consider a system of two Einstein solids, A=4 and B=6, sharing a total of 10 units...
Consider a system of two Einstein solids, A=4 and B=6, sharing a total of 10 units of energy. Assume that the solids are weakly coupled, and that the total energy is fixed. How many different macrostates are available to this system? How many different microstates are available to this system? Assuming that this system is in thermal equilibrium, what is the probability of finding all the energy in solid A? What is the probability of finding exactly half of the...
Consider a system of two Einstein solids, A=4 and B=6, sharing a total of 10 units...
Consider a system of two Einstein solids, A=4 and B=6, sharing a total of 10 units of energy. Assume that the solids are weakly coupled, and that the total energy is fixed. a. How many different macrostates are available to this system? b. How many different microstates are available to this system? c. Assuming that this system is in thermal equilibrium, what is the probability of finding all the energy in solid A? d. What is the probability of finding...
Consider the two (excess return) index model regression results for A and B: RA = –1.8%...
Consider the two (excess return) index model regression results for A and B: RA = –1.8% + 2RM R-square = 0.640 Residual standard deviation = 12.6% RB = 1.4% + 1RM R-square = 0.590 Residual standard deviation = 11.4% If rf were constant at 6% and the regression had been run using total rather than excess returns, what would have been the regression intercept for stock A? (Negative value should be indicated by a minus sign. Round your answer to...
Consider the two (excess return) index model regression results for stock A and B RA =...
Consider the two (excess return) index model regression results for stock A and B RA = 0.01 + 1.2RM R2 of 0.576; Std deviation of error term of 10.3% RB = -0.02 + 0.8RM R2 of 0.436; Std deviation of error term of 9.1% a) Which stock has more firm-specific risk? Explain [4 points] b) Which has greater market risk? Explain [4 points] c) For which stock does market movement explain a grater fraction of return variability? Explain [4 points]...
Consider the two (excess return) index-model regression results for stocks A and B. The risk-free rate...
Consider the two (excess return) index-model regression results for stocks A and B. The risk-free rate over the period was 8%, and the market’s average return was 14%. Performance is measured using an index model regression on excess returns. Stock A Stock B Index model regression estimates 1% + 1.2(rM − rf) 2% + 0.8(rM − rf) R-square 0.665 0.481 Residual standard deviation, σ(e) 11.8% 20.6% Standard deviation of excess returns 23.1% 27.9% a. Calculate the following statistics for each...
Consider the two (excess return) index-model regression results for stocks A and B. The risk-free rate...
Consider the two (excess return) index-model regression results for stocks A and B. The risk-free rate over the period was 7%, and the market’s average return was 14%. Performance is measured using an index model regression on excess returns. Stock A Stock B Index model regression estimates 1% + 1.2(rM − rf) 2% + 0.8(rM − rf) R-square 0.635 0.466 Residual standard deviation, σ(e) 11.3% 20.1% Standard deviation of excess returns 22.6% 26.9% a. Calculate the following statistics for each...
Problem 24-9 Consider the two (excess return) index-model regression results for stocks A and B. The...
Problem 24-9 Consider the two (excess return) index-model regression results for stocks A and B. The risk-free rate over the period was 5%, and the market’s average return was 15%. Performance is measured using an index model regression on excess returns. Stock A Stock B Index model regression estimates 1% + 1.2(rM ? rf) 2% + 0.8(rM ? rf) R-square 0.617 0.457 Residual standard deviation, ?(e) 11% 19.8% Standard deviation of excess returns 22.3% 26.3% a. Calculate the following statistics...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT