In: Statistics and Probability
The water works commission needs to know the mean household usage of water by the residents of a small town in gallons per day. Assume that the population standard deviation is 2.2 gallons. The mean water usage per family was found to be 15.8 gallons per day for a sample of 669 families. Construct the 90% confidence interval for the mean usage of water. Round your answers to one decimal place.
Solution :
Given that,
= 15.8 gallons
= 2.2 gallons
n = 669
At 90% confidence level the z is ,
= 1 - 90% = 1 - 0.90 = 0.10
/ 2 = 0.10 / 2 = 0.05
Z/2 = Z0.05 = 1.645
Margin of error = E = Z/2* (/n)
= 1.645 * (2.2 / 669)
= 0.1
At 90% confidence interval estimate of the population mean is,
- E < < + E
15.8 - 0.1 < < 15.8 + 0.1
15.7 < < 15.9
(15.7 , 15.9)