In a recent year, Delaware had the highest per capita annual income with $51,803. Assume that...

In a recent year, Delaware had the highest per capita annual income with $51,803. Assume that σ = $4,850. A random sample of 39 state residents were selected.

What is the distribution of the sample mean income?

What is the probability that the sample mean income is greater than $50,800?

Solutions

Expert Solution

Solution :

Given that ,

mean = = 51803

standard deviation = = 4850

n = 39

= = 51803 and

= / n = 4850/ 39 = 776.6215

P( > 50800) = 1 - P( < 50800)

= 1 - P(( - ) / < (50800 - 51803) / 776.6215)

= 1 - P(z < -1.29)

= 1 - 0.0985 Using standard normal table.

= 0.9015

Probability = 0.9015

orchestra answered 1 year ago

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