Question

In: Statistics and Probability

An exhaustive study of all active Facebook accounts was recently conducted by Facebook. One variable Facebook...

An exhaustive study of all active Facebook accounts was recently conducted by Facebook. One variable Facebook recorded was the number of friends X of each Facebook user. Suppose X has expected value E(X) = 180 and standard deviation SD(X) = 280.7. Since the possible values of X are only integers and since the distribution of X is highly skewed to the right, the distribution of X cannot be described by a normal model. Suppose you select a random sample of 35 Facebook users and record the number of Facebook friends each user has.

A) What is the probability that the 35 Facebook users in your sample have a sample mean number of friends x greater than 177?

(use 4 decimal places in your answer)

B) What is the probability that the 35 Facebook users in your sample have a sample mean number of friends x less than 183?

(use 4 decimal places in your answer)

Solutions

Expert Solution

Solution :

Given that ,

mean = = 180

standard deviation = = 280.7

= / n = 280.7 / 35 = 47.4470

A)

P( > 177) = 1 - P( < 177)

= 1 - P[( - ) / < (177 - 180) / 47.4470]

= 1 - P(z < -0.06)

= 1 - 0.4761

= 0.5239

Probability = 0.5239

B)

P( < 183) = P(( - ) / < (183 - 180) / 47.4470)

= P(z < 0.06)

= 0.5239

Probability = 0.5239

  


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