Question
In: Statistics and Probability
A telephone service representative believes that the proportion of customers completely satisfied with their local telephone...
A telephone service representative believes that the proportion of customers completely satisfied with their local telephone service is different between the Midwest and the West. The representative's belief is based on the results of a survey. The survey included a random sample of 760 midwestern residents and 680 western residents. 37% of the midwestern residents and 46% of the western residents reported that they were completely satisfied with their local telephone service. Find the 90% confidence interval for the difference in two proportions.
1. Find the point estimate that should be used in constructing the confidence interval.
2. Find the margin of error. Round your answer to six decimal place
Solutions
orchestra answered 1 year agoRelated Solutions
A telephone service representative believes that the proportion of customers completely satisfied with their local telephone...
A telephone service representative believes that the proportion
of customers completely satisfied with their local telephone
service is different between the Midwest and the South. The
representative's belief is based on the results of a survey. The
survey included a random sample of 1120 midwestern residents and
1260 southern residents. 37% of the midwestern residents and 49% of
the southern residents reported that they were completely satisfied
with their local telephone service. Find the 80%
confidence interval for the difference...
A telephone service representative believes that the proportion of customers completely satisfied with their local telephone...
A telephone service
representative believes that the proportion of customers completely
satisfied with their local telephone service is different between
the Midwest and the West. The representative's belief is based on
the results of a survey. The survey included a random sample of 760
midwestern residents and 680 western residents. 37% of the
midwestern residents and 46% of the western residents reported that
they were completely satisfied with their local telephone service.
Find the 90% confidence interval for the difference...
A telephone service representative believes that the proportion of customers completely satisfied with their local telephone...
A telephone service representative believes that the proportion
of customers completely satisfied with their local telephone
service is different between the West and the Northeast. The
representative's belief is based on the results of a survey. The
survey included a random sample of 12401240 western residents and
13001300 northeastern residents. 46%46% of the western residents
and 35%35% of the northeastern residents reported that they were
completely satisfied with their local telephone service. Find the
98%98% confidence interval for the difference...
The proportion of customers who are completely satisfied in a recent satisfaction survey of 300 customers...
The proportion of customers who are completely satisfied in a
recent satisfaction
survey of 300 customers at XYC Inc.
is found to be 0.26. (6
points)
Test the hypothesis that the population proportion of customers
who are completely satisfied is greater than 0.22 using the
critical value approach and a 0.05 level of significance.
Test the hypothesis that the population proportion of customers
who are
completely satisfied is less than
0.30 using the p-value approach and a
0.05 level of...
B. The proportion of customers who are completely satisfied in a recent satisfaction survey of 300...
B. The proportion of customers who are completely satisfied in a
recent satisfaction survey of 300 customers at XYC Inc. is found to
be 0.26. Test the hypothesis that the population
proportion of customers who are completely satisfied is greater
than 0.22 using the critical value approach and a 0.05 level of
significance. e Test the hypothesis that the population proportion
of customers who are completely satisfied is less than 0.30 using
the p-value approach and a 0.05 level of...
A luxury hotel believes that 90% of their customers are very satisfied with its service. A...
A luxury hotel believes that 90% of their customers are very
satisfied with its service. A random sample of 120 guests were
surveyed to determine how satisifed they are with the service and
accommodations at the hotel.
a. Describe the random variable for this probability
distribution (i.e., what type of variable, what is the probability
distribution, what does the variable represent, what are it's
possible values, etc.).
b. What is the probability that at least 110 of the people in...
Consider the job of customer service representative who takes telephone calls from customers of a retailer...
Consider the job of customer service representative who takes
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A store surveys customers to see if they are satisfied with the service they receive. Samples...
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An automobile manufacturer would like to know what proportion of its customers are not satisfied with...
An automobile manufacturer would like to know what proportion of
its customers are not satisfied with the service provided by the
local dealer. The customer relations department will survey a
random sample of customers and compute a 96% confidence interval
for the proportion who are not satisfied. (a) Past studies suggest
that this proportion will be about 0.23. Find the sample size
needed if the margin of the error of the confidence interval is to
be about 0.015. (You will...
An automobile manufacturer would like to know what proportion of its customers are not satisfied with...
An automobile manufacturer would like to know what proportion of
its customers are not satisfied with the service provided by the
local dealer. The customer relations department will survey a
random sample of customers and compute a 96% confidence interval
for the proportion who are not satisfied.
(a) Past studies suggest that this proportion will be about
0.15. Find the sample size needed if the margin of the error of the
confidence interval is to be about 0.015. (You will...
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