Question

It is reported in USA Today that the average flight cost nationwide is $442.28. You have never paid close to that amount and you want to perform a hypothesis test that the true average is actually greater than $442.28. What are the appropriate hypotheses for this test?

Question 1 options:

	1) HO: μ ≤ 442.28 HA: μ > 442.28
	2) HO: μ < 442.28 HA: μ ≥ 442.28
	3) HO: μ > 442.28 HA: μ ≤ 442.28
	4) HO: μ ≥ 442.28 HA: μ < 442.28
	5) HO: μ = 442.28 HA: μ ≠ 442.28

Question 2 (1 point)

In the year 2000, the average vehicle had a fuel economy of 23.13 MPG. You are curious as to whether the average in the present day is greater than the historical value. The hypotheses for this scenario are as follows: Null Hypothesis: μ ≤ 23.13, Alternative Hypothesis: μ > 23.13. A random sample of 43 vehicles shows an average economy of 24.15 MPG with a standard deviation of 6.69 MPG. What is the test statistic and p-value for this test?

Question 2 options:

	1) Test Statistic: -1, P-Value: 0.1616
	2) Test Statistic: 1, P-Value: 0.3232
	3) Test Statistic: -1, P-Value: 0.8384
	4) Test Statistic: 1, P-Value: 0.8384
	5) Test Statistic: 1, P-Value: 0.1616

Question 3 (1 point)

Consumers Energy states that the average electric bill across the state is $41.553. You want to test the claim that the average bill amount is actually greater than $41.553. The hypotheses for this situation are as follows: Null Hypothesis: μ ≤ 41.553, Alternative Hypothesis: μ > 41.553. A random sample of 47 customer's bills shows an average cost of $43.307 with a standard deviation of $8.0202. What is the test statistic and p-value for this test?

Question 3 options:

	1) Test Statistic: -1.499, P-Value: 0.0703
	2) Test Statistic: 1.499, P-Value: 0.0703
	3) Test Statistic: -1.499, P-Value: 0.9297
	4) Test Statistic: 1.499, P-Value: 0.1406
	5) Test Statistic: 1.499, P-Value: 0.9297

Question 4 (1 point)

A medical researcher wants to determine if the average hospital stay of patients that undergo a certain procedure is different from 8.7 days. The hypotheses for this scenario are as follows: Null Hypothesis: μ = 8.7, Alternative Hypothesis: μ ≠ 8.7. If the researcher takes a random sample of patients and calculates a p-value of 0.0197 based on the data, what is the appropriate conclusion? Conclude at the 5% level of significance.

Question 4 options:

	1) The true average hospital stay of patients is equal to 8.7 days.
	2) The true average hospital stay of patients is significantly longer than 8.7 days.
	3) We did not find enough evidence to say a significant difference exists between the true average hospital stay of patients and 8.7 days.
	4) The true average hospital stay of patients is significantly shorter than 8.7 days.
	5) The true average hospital stay of patients is significantly different from 8.7 days.

Answer 1

1
In USA Today that the average flight cost nationwide is $442.28. You have never paid close to that amount and you want to perform a hypothesis test that the true average is actually greater than $442.28. The appropriate hypotheses for this test

OPTION 1

1)	HO: μ ≤ 442.28 HA: μ > 442.28

2


1. Null Hypothesis 23.13
2. Null Hypophesis > 23.13

The test hypothesis is

This is a one-sided test because the alternative hypothesis is formulated to detect the difference from the hypothesized mean on the upper side
Now, the value of test static can be found out by following formula:

Using Excel's function =T.DIST.RT(t_0,n-1), the P-value for t_0 = 0.9998 in an upper-tailed t-test with 42 degrees of freedom can be computed as

OPTION 5) Test Statistic = 1, P-Value = 0.1616

3


1. Null Hypothesis 41.553
2. Null Hypophesis > 41.553

The test hypothesis is

This is a one-sided test because the alternative hypothesis is formulated to detect the difference from the hypothesized mean on the upper side
Now, the value of test static can be found out by following formula:

Using Excel's function =T.DIST.RT(t_0,n-1), the P-value for t_0 = 1.4993 in an upper-tailed t-test with 46 degrees of freedom can be computed as

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