Question

In: Biology

1. Put the general step in order necessary to create bacteria capable of producing human insulin....

1. Put the general step in order necessary to create bacteria capable of producing human insulin.

step 1

step 2

step 3

step 4

step 5

a. splice the human insulin DNA into the bacterial plasmid

b. Cut the bacteria plasmid with HindIII

c. Treat bacterial to induce transformation

d. culture bacteria and isolate the protein

e. cut the bacteria plasmid with BamH1

f. isolate and cut the human insulin gene with BamH1

2. Human DNA cut with BamH1 can be joined to

a. human DNA cut with HindiIII

b. bacteria DNA cut with BamH1

c. Human DNA that is uncut

d. none of the above

e. bacterial DNA that is uncut

3. which of the following could not be a recognition site of a palindromic restriction endonuclease?

a. GAATTC

CTTAAG

b. ATCGAT

TAGCTA

c. CTGCAG
GACGTC

d. GCTTGC

CGAACG

e. GGATCC

CCTAGG

4. Because eukaryotic genes contain introns, they cannot be translated by bacteria, which lack RNA-splicing machinery. But if you want to engineer a bacterium to produce a eukaryotic protein (such as insulin), you can synthesize a gene without introns. The best way to do this is to:

a. alter the bacteria so that they can splice RNA

b. Use a restriction enzyme to remove introns from the gene

c. work backward from mRNA to make a version of the gene without introns

5. The gene for human growth hormone (HGH) can be inserted into the genome of bacteria. The bacteria that take up the HGH gene can transcribe and translate this gene into small quantities of this protein. How is this technology possible?

a. bacteria employ the same genetic code as humans

b. Humans require HGH grow normally.

c. Reproductive cloning is possible only in bacteria

d. The genomes of bacteria and human are similar

6. In the process of gel electrophoresis, DNA segment can be separated from each other based on?

a. the ratio of thymine to adenine base-pairs compared to cytosine to guanine base-pairs

b. the fact that some segments are negatively charged while others are positively charged.

c. the fact that some of the DNA will be single-stranded while others will be double-stranded

d. the length of each base-pair segment

7. which of the following is not true about restriction endonucleases?

a. restriction endonucleases cut in an internal region of the DNA

b. Restriction endonucleases are used by bacteria to cut viral DNA

c. restriction endonuclease can produce "sticky ends."

d. Restriction endonucleases are only useful to scientists if they cut specific recognition sites.

8. you are given a linear piece of DNA Gel electrophoresis and restriction digestion results in the following data:

DNA + Ecoli produces two bands of 800bp and 200 bp

DNA + BamHI produces one band of 500 bp

DNA + Ecoli + BamHI produces three bands of 500bp, 300bp, and 200bp

Which of the following is not true?

a. there is a single Ecoli recognition site in the DNA

b. There are two Ecoli recognition sites in the DAN

c. There is a single BamHI recognition site in the DAN

d. the uncut DNA would produce a single band of 1.000bp

9. sequences in DNA that restriction enzymes bind to and cut are mostly:

a. random sequences

b. symmetrical about the midpoint

c. antiparallel

d. not symmetrical about the midpoint.

10. the single strand ends of DNA molecules can be joined together by:

a. restriction endonucleases

b. DNA polymerase

c. RNA polymerase

d. DNA ligase

11. If a circular piece of DNA has three sites for a particular restriction enzyme, how many fragments will be generated by complete digestion with that enzyme .................

Expert Solution

1.

Step 1: Isolate and cut the human insulin gene with BamH1

Step 2: Cut the bacteria plasmid with BamH1

Step 3: Splice the human insulin DNA into the bacterial plasmid

Step 4: Treat bacterial to induce transformation

Step 5: Culture bacteria and isolate the protein

2. Option B is correct.

For an insert to be ligated into a vector, both of them must contain compatible sticky ends.

Sticky ends created in the human gene by Bam HI are compatible with bacterial DNA that is cut with BamHI.

3. Option A is correct.

A palindromic sequence is read the same in both orientations.

The top strand sequence = 5'-GAATTC-3'

The bottom strand also reads the same in 5'-3' direction.

4. Option C is correct.

To clone a eukaryotic gene into a prokaryotic host for protein expression, only coding sequence has to be used. The coding sequence which is devoid of introns can be obtained by the reverse transcription of mRNA.

5. Option A is correct.

The genetic code is universal.

6. Option D is correct.

Gel electrophoresis is based on size differences between DNA strands.

7. Option D is correct.

8. Option B is correct.

9. Option B is correct.

10. Option D is correct.

11. If a circular piece of DNA has three sites for a particular restriction enzyme, the number of fragments generated by complete digestion with that enzyme = 3

gladiator answered 1 year ago

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