In: Statistics and Probability
Solution :
Given that,
Point estimate = sample mean = = 100.75
sample standard deviation = s = 5.46
sample size = n = 12
Degrees of freedom = df = n - 1 = 12 - 1 = 11
t /2,df = t0.025,11 = 2.201
Margin of error = E = t/2,df * (s /n)
= 2.201 * ( 5.46/ 12)
Margin of error = E = 3.47
The 95% confidence interval estimate of the population mean is,
- E < < + E
100.75 - 3.47 < < 100.75 + 3.45
97.28 < < 104.22
(97.28 , 104.22)