In: Statistics and Probability
Solution :
Given that,
Point estimate = sample mean =
= 100.75
sample standard deviation = s = 5.46
sample size = n = 12
Degrees of freedom = df = n - 1 = 12 - 1 = 11
t
/2,df = t0.025,11 = 2.201
Margin of error = E = t/2,df
* (s /
n)
= 2.201 * ( 5.46/
12)
Margin of error = E = 3.47
The 95% confidence interval estimate of the population mean is,
- E <
<
+ E
100.75 - 3.47 <
< 100.75 + 3.45
97.28 <
< 104.22
(97.28 , 104.22)