In: Statistics and Probability
(Minitab)
Ice Cream Sales
Answer the following questions, showing any calculations involved. Include this document along with the graphs created with Minitab in your submission.
Independent variable: __________________ Dependent variable: __________________
Regression Equation: ______________________________
Slope: _______________ y-Intercept: _______________
Ice Cream Data
Temperature F Sales
57.6 215
61.5 325
53.4 185
59.4 332
65.3 406
71.8 522
66.9 412
77.2 614
74.1 544
64.6 421
72.7 445
63.0 408
64.4 250
66.2 345
73.4 459
62.6 349
66.2 311
73.4 463
59.0 262
73.4 462
55.4 274
75.2 459
55.4 252
69.8 426
57.2 289
69.8 438
57.2 311
68.0 448
64.4 257
73.4 477
64.4 319
73.4 479
71.6 490
60.8 347
59.0 349
68.0 436
Identify the independent (predictor) and dependent
(response) variables. [2 pts]
Independent variable: Temperature Dependent variable: Sales
From the scatter diagram, does there seem to be a linear
correlation? If so, is it strong or weak? Is it positive or
negative? What does it say about the relationship between the 2
variables? [4 pts]
Yes there is linear correlation. It a strong. It is positve. As the
temperature increases, the sales also increases.
Use your scatter diagram to answer the following
questions.
If you calculated the linear correlation coefficient for
this data to be r = –0.75, explain in one sentence how you know
this is incorrect. [2 pts]
It is incorrect since, intitutively the relationship between the
two variables cannot be negative or inverse, that is as one
increase, the other one decreases.
If you calculated the linear correlation coefficient for
this data to be r = 1.20, explain in one sentence how you know this
is incorrect. [2 pts]
It is incorrect, because the correlation can be more than 1.
What is the correlation coefficient, r. Based on the
correlation coefficient, how accurate do you think your regression
equation is at making a prediction?
Why? [2 pts]
The correlation is 0.88.
From the correlation we have can find the coefficient of
determination = 0.94 ( it is the square root of the
correlation).
It is the measure of the amount of variability in y explained by x.
Its value lies between 0 and 1. Greater the value, better is the
model. In this case, it 94%, hence the model is good